Answer:
B) A one-sample t-test for population mean would be used.
Step-by-step explanation:
The complete question is shown in the image below.
The marketing executive is interested in comparing the mean number of sales of this year to that of previous year.
The marketing executive already has the value of mean from previous year and uses a sample to calculate the mean and standard deviation of sales for the current year.
Since, data is being collected for one sample only this limits us to chose between one sample test for mean. So now the possible options are one sample t-test for population mean and one sample t-test for population mean.
If we read the statement we can see that we have the value of sample mean and sample standard deviation. Value of population standard deviation is unknown. In cases where value of population standard deviation is not known and sample standard deviation is given, t-test is used.
Therefore, we can conclude that A one-sample t-test for population mean would be used.
Answer: f(2) = 4
Step-by-step explanation:
F(x) and g(x) are said to be continuous functions
Lim x=2 [3f(x) + f(x)g(x)] = 36
g(x) = 2
Limit x=2
[3f(2) + f(2)g(2)] = 36
[3f(2) + f(2) . 6] = 36
[3f(2) + 6f(2)] = 36
9f(2) = 36
Divide both sides by 9
f(2) = 36/9
f(2) = 4
Given:
<span>12-foot wire is secured from the ground to the tree at a point 10 feet off the ground.
The tree meets the ground at a right angle.
When you visualize the scenario, the 12 foot wire would be the measure of the hypotenuse and the 10 feet off the ground will be the short leg or opposite. The long leg or adjacent is unknown.
We need to solve for sine theta because the value of hypotenuse and opposite is given.
sin </span>θ = opposite / hypotenuse
sin θ = 10 feet / 12 feet
sin θ = 0.833
θ = 0.83 / sin
θ = 56°
The wire would meet the ground at approximately 56° angle.
76,500/100,000 divide by 100
765/1,000. divide by 5
153/500