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2 years ago

Drag each tile to the correct box. Not all tiles will be used.

Mathematics

1 answer:

Zina [86]2 years ago

5 0

Answer:

$1,100 at 3.2% for 3 years -> $105.60

$990 at 3.15% for 4 years -> $124.74

$1,025 at 2.8% for 5 years -> $143.5

Step-by-step explanation:

Simple interest formula is:

A = P*(1 + r*t)

where A if final account, P is principal, r is annual interest rate (as decimal) and t is time in years

Interest earned is A - P, then:

I = P*(1 + r*t) - P = P(1 + r*t - 1) = P*r*t

If P = $1100, r = 0.032 and t = 3, then:

I = 1100*0.032*3 = $105.6

If P = $990, r = 0.0315 and t = 4, then:

I = 990*0.0315*4 = $124.74

If P = $1025, r = 0.028 and t = 5, then:

I = 1025*0.028*5 = $143.5

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Karolina [17]

A. How many kilowatt hours of electricity did the Smiths use during February?

Kilowatt hours of electricity the Smiths used during February:
Meter read on March 1 - meter read on February 1 =
20,288 kilowatt hours - 19,423 kilowatt hours =
865 kilowatt hours
Answer: The Smiths used 865 kilowatt hours of electricity during February

b. How many kilowatt hours did they use during March?

Kilowatt hours of electricity the Smiths used during March:
Meter read on April 1 - meter read on March 1 =
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2 years ago

Write a number that is greater than 4.508 but less than 4.512

Lelechka [254]

4.509 is greater that 4.508 and less than 4.512

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2 years ago

Read 2 more answers

The fraction of defective integrated circuits produced in a photolithography process is being studied. A random sample of 300 ci

Olenka [21]

Answer:

The correct answer is

(0.0128, 0.0532)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$

For this problem, we have that:

In a random sample of 300 circuits, 10 are defective. This means that $n = 300$ and $\pi = \frac{10}{300} = 0.033$

Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool.

So $\alpha$ = 0.05, z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 - 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0128$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 + 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0532$

The correct answer is

(0.0128, 0.0532)

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1 year ago

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andriy [413]

Answer:

trigonal bypyramidal

Step-by-step explanation:

It's difficult to explain without a drawing or a model, but it would basically arrange itself into two triangle based pyramids connected to each other at the base, which is trigonal bypyramidal.

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1 year ago

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drek231 [11]

Answer:

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