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Vlad [161]
2 years ago
12

Jacob has a bag of his favorite marbles. It has 3 red marbles, 4 blue, and 10 of his most favorite color, neon orange. What is t

he probability that, if he removes 2 marbles without looking and without replacement, he will get two orange marbles
Mathematics
1 answer:
drek231 [11]2 years ago
7 0

Answer:

P(1\ and\ 2) = 0.3309

Step-by-step explanation:

Given

Red = 3

Blue = 4

Orange=10

Required

Probability of selecting 2 orange marbles

The total number of marbles is:

Total = Red + Blue + Orange

Total = 3 + 4 + 10

Total = 17

The probability that the first selection is orange is:

P(1) = \frac{10}{17}

Because it is a selection without replacement, the number of orange marbles and the total number of marbles would decrease by 1, respectively.

So, the probability that the selection is orange is:

P(2) = \frac{10-1}{17-1}

P(2) = \frac{9}{16}

The required probability is:

P(1\ and\ 2) = P(1) * P(2)

P(1\ and\ 2) = \frac{10}{17} * \frac{9}{16}

P(1\ and\ 2) = \frac{10*9}{17*16}

P(1\ and\ 2) = \frac{90}{272}

P(1\ and\ 2) = 0.3309

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