An=a1(r)^(n-1)
a1=first erm
r=common ratio
firs term is -5
we times each term by 5 to get next term so r=5

is the explicit formula
<span>If Mary earns 7$ an hour, we need to multiplicate 7$ by the number of hours worked for the entire week so we can get the salary per week. And when we want to know how many hours she had worked, we have to "transform" the equation :
Salary per week = salary per hours x worked hours
Here, we know to informations : salary per hours and salary per week.
Worked hours = salary per week / salary per day
Worked hours = 143.50 / 7
Worked hours = 20.5
The greatest number of hours thats he works is 20h30.</span>
Answer:
The answer would be A. 55.
Step-by-step explanation:
For the 35% you would take your 200 and divide it by 2 and have two 100's. Since 35% is out of 100% you could take 35 from each 100 and add them together to get 70.
For the 3/8 you would divide and get .375 then you would multiply that by 200 which would give you 75 yellow tags. Then you would add 75 and 70 and get 145. Then subtract 145 from 200 to get 55. Therefore there would be 55 red tags.
You could rewrite this as double brackets, as you are multiplying together two sets of two terms. It would then look like:
(8i + 6j)(4i + 5j)
and you can expand by multiplying together all of the terms
8i × 4i = 32i²
8i × 5j = 40ij
6j × 4i = 24ij
6j × 5j = 30j²
To get your final answer, you then just need to add together all of the like terms, and get 32i² + 30j² + 64ij
I hope this helps!
Answer:
No. There is not enough evidence to support the claim that the population standard deviation is different from $12.
Step-by-step explanation:
The null hypothesis is that the true standard deviation is 12.
The alternative hypothesis is that the true standard deviation differs from 12.
We can state:

The significance level is 0.10.
The sample size is n=15, so the degrees of freedom are:

The sample standard deviation is 9.25.
The test statistic is

The critical values for rejecting the null hypothesis are:

As T=8.32 is within the acceptance region (5.01, 24.74), the null hypothesis failed to be rejected.
There is not enough evidence to support the claim that the population standard deviation is different from $12.