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Rudiy27
2 years ago
5

The meat department of a supermarket sells ground beef in approximate 1 lb packages, but there is some variability. A random sam

ple of 65 packages yielded a mean of 1.05 lbs and a standard deviation of .23 lbs. What is the 90% Confidence Interval for this problem?
Mathematics
1 answer:
grin007 [14]2 years ago
6 0

Answer:

1.05 ± 0.05 lbs

Step-by-step explanation:

Hi!

We can calculate this interval with the z-score of the 90% which is (by convention) 1.645

The interval is calculated as follows:

x_m \pm 1.654(\frac{\sigma}{\sqrt n})

where x_m is the mean, σ the standar deviation and n is the number of samples:

replacing these values we get:

1.05 \pm (1.645 \times \frac{0.23}{\sqrt 65})\\1.05 \pm 0.046

*rounded to the first decimal*

1.05 ± 0.05

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We use the conditional probability formula to solve this question. It is

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Event B: Is very active.

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