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algol [13]
2 years ago
11

the x-values in the table for f(x) were multiplied by -1 to create the table for g(x) what isbthe relationship between the graph

s of the two functions

Mathematics
2 answers:
kenny6666 [7]2 years ago
7 0

Answer: The answer is C

denpristay [2]2 years ago
4 0

Answer: g(x) is the image of f(x)


Step-by-step explanation:

multiplying the x value by -1 means you reflect that point across y-axis, therefore, g(x) is the reflection of f(x) across y-axis.

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A sample of 2,845 auto workers was selected to learn if they would go on strike. Over 50% of those in the sample declared they w
bogdanovich [222]

Answer:

This condition is true.

Step-by-step explanation:

A sample of 2,845 auto workers was selected to learn if they would go on strike.

Over 50% of those in the sample declared they would strike.

We can assume that the majority of all auto workers favor a strike. This is true because, in the sample, it is declared that 50% of workers would strike.

And this sample represents the whole majority or population. Hence we can say that a majority of all auto workers favor a strike.

5 0
2 years ago
Which equation represents a line that passes through (–2, 4) and has a slope of 2/5? y – 4 = 2/5 (x 2) y 4 = 2/5 (x – 2) y 2 = 1
Natali5045456 [20]
Equation of a line is given by y - y1 = m(x - x1); where m is the slope.
y - 4 = 2/5 (x - (-2))
y - 4 = 2/5 (x + 2)
7 0
2 years ago
Read 2 more answers
Find the coordinates of the center of the following circle. (x + 3)2 + (y - 6)2 = 24
irga5000 [103]
<span>the equation of a circle with the center at (h,k0 is given by the equation where the r is obviously the radius of the circle then do (x+3) ^2
(y-6)^2= 24 which shows that the center is = to (-3,6)
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4 0
2 years ago
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Let P2 be the vector space of all polynomials of degree 2 or less, and let H be the subspace spanned by 10x2+4xâ1, 3xâ4x2+3, and
lord [1]

I suppose

H=\mathrm{span}\{10x^2+4x-1,3x-4x^2+3,5x^2+x-1\}

The vectors that span H form a basis for P_2 if they are (1) linearly independent and (2) any vector in P_2 can be expressed as a linear combination of those vectors (i.e. they span P_2).

  • Independence:

Compute the Wronskian determinant:

\begin{vmatrix}10x^2+4x-1&3x-4x^2+3&5x^2+x-1\\20x+4&3-8x&10x+1\\20&-8&10\end{vmatrix}=-6\neq0

The determinant is non-zero, so the vectors are linearly independent. For this reason, we also know the dimension of H is 3.

  • Span:

Write an arbitrary vector in P_2 as ax^2+bx+c. Then the given vectors span P_2 if there is always a choice of scalars k_1,k_2,k_3 such that

k_1(10x^2+4x-1)+k_2(3x-4x^2+3)+k_3(5x^2+x-1)=ax^2+bx+c

which is equivalent to the system

\begin{bmatrix}10&-4&5\\4&3&1\\-1&3&-1\end{bmatrix}\begin{bmatrix}k_1\\k_2\\k_3\end{bmatrix}=\begin{bmatrix}a\\b\\c\end{bmatrix}

The coefficient matrix is non-singular, so it has an inverse. Multiplying both sides by that inverse gives

\begin{bmatrix}k_1\\k_2\\k_3\end{bmatrix}=\begin{bmatrix}-\dfrac{6a-11b+19c}3\\\dfrac{3a-5b+2c}3\\\dfrac{15a-26b+46c}3\end{bmatrix}

so the vectors do span P_2.

The vectors comprising H form a basis for it because they are linearly independent.

4 0
2 years ago
How do I solve w(x)=4x 5; find w(-8)?
Andrei [34K]
Plug -8 in for x: 4(-8) + 5 solve: -32 + 5 -27
4 0
2 years ago
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