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qaws [65]
1 year ago
15

Ebuka's monthly rent is \$750$750dollar sign, 750. If Ebuka pays the rent late, his landlord charges 4\%4%4, percent interest pe

r week that the payment is late.
Mathematics
1 answer:
dem82 [27]1 year ago
5 0

Answer: R(t) = 750 + 0.04t

Step-by-step explanation:

Here's the complete question:

Ebuka's monthly rent is $750. If Ebuka pays the rent late, his landlord charges 4% interest per week that the payment is late. Write a function that gives the total cost R(t), in dollars, of Ebuka's rent if he pays it t weeks late.

The above question will be represented by:

R(t) = $750 + (4% × t)

R(t) = 750 + (4/100 × t)

R(t) = 750 + 0.04t

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The subjects of a study by Dugoff et al. (A-5) were 10 obstetrics and gynecology interns at the University of Colorado Health Sc
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Answer:

The 95 percent confidence interval for the mean of the population from which the study subjects may be presumed to have been drawn is (19.1269, 32.6730).

Step-by-step explanation:

Intern            No. of Breast

Number        Exams Performed               X²

1                         30                                  900

2                        40                                 1600

3                        8                                        64

4                        20                                   400

5                          26                                 676

6                           35                               1225

7                            35                               1225

8                            20                                400

9                             25                              625

<u>10                                 20                        400 </u>

<u>                                   </u><u> ∑ 259                  ∑ 7515</u>

Mean= X`= ∑x/n= 259/10= 25.9

Variance = s²= 1/n-1[∑X²- (∑x)²/n]

= 1/0[7515- (259)²/10]= 1/9[7515- 6708.1]

= 806.9/9=89.655= 89.66

Standard Deviation= √89.655= 9.4687

Hence

The value of t with significance level alpha= 0.05 and 9 degrees of freedom  is t(0.025,9)= 2.262

The 95 % Confidence interval is given by

x`±t(∝,n-1) s/√n

So Putting the values

25.9± 2.262( 9.4687/√10)

= 25.9 ±2.262 (2.9943)

= 25.9 ± 6.7730

= 25.9 +6.7730=32.6730

25.9 -6.7730= 19.1269

= 19.1269, 32.6730

The 95 percent confidence interval for the mean of the population from which the study subjects may be presumed to have been drawn is (19.1269, 32.6730).

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