1.)
zChest -> (91.2-75)/4.8=-3.4zWaist -> (80.9-56.5)/9.8≈-2.5zHips -> (93.7-72)/6.8≈-3.2It would be Ken's chest because the difference between the doll and an averaged human male is the greatest
2.)
zChest -> (82.3-90.3)/4.7≈-1.45zWaist -> (40.7-69.8)/4.7≈-6.19zHips -> (72.7-97.9)/5.4≈-4.7
Yes because the waist is far too thin compared to an averaged human woman
3.)
zJill -> (680-500)/100=1.8zJack -> (27-18)/6=1.5
4.)
It would be Jill because she has the higher z-score
5.)
$520-420=80$50=SDs$80(1 SD/50)=1.6 SD
This is just a basic proportion. 5/8 = x/12. So the 5 foot tall women would have a 7.5 foot shadow.
<span>0.375 * a^2 b^3 c^5 x^(-4) y^(-3) z^(-1) would be your answer.</span>
Answer:
a.) The mean of the six layered plywood is 30 mm
The standard deviation is 0.49 mm
b.) That the thickness is less than 28 mm has a probability of 0.000022.
Step-by-step explanation:
There are six layers in a plywood that is considered. It is also given that the layers are independent and normally distributed.
The thickness of the layers of the plywood have a mean,
= 5 mm
and a standard deviation,
= 0.2 mm.
a.) Therefore the mean of the six layered plywood is = 6
= 6 × 5 mmm
= 30 mm
The standard deviation of the six layered plywood =
=
= 0.49 mm
b.) We are given to find that the probability of the plywood is less than 28 mm thick.
P( thickness < 28 mm)
P( Z <
) = P(Z <
) ⇒ P( Z < -4.082) = 0.000022