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1 year ago

12

A seamstress has a piece of cloth that is 3 yards long. She cuts it into shorter lengths of 16 inches each. How many of the shor

ter pieces can she cut?

1 answer:

harkovskaia [24]1 year ago

4 0

She can cut 6 pieces. Here's how.
Three yards are 108 inches, 16 can go into 108, 6.75 times.

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If 36a=45/b, then ab=

Ronch [10]

Answer:

$1.25$

Step-by-step explanation:

$let \: a = x \: and \: b = y$

$36x = \frac{45}{y}$

$36xy = 45$

$xy = \frac{45}{36}$

$xy = 1.25$

$therefore \: ab \: is \: 1.25$

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2 years ago

For a standardized psychology examination intended for psychology majors, the historical data show that scores have a mean of 52

Ludmilka [50]

Answer:

the probability that a sample of the 35 exams will have a mean score of 518 or more is <em> 0.934 </em>or<em> 93.4%</em>.

Step-by-step explanation:

This is s z-test because we have been given a sample that is large (greater than 30) and also a standard deviation. The z-test compares sample results and normal distributions. Therefore, the z-statistic is:

(520 - 518) / (180/√35)

= 0.0657

Therefore, the probability is:

P(X ≥ 0.0657) = 1 - P(X < 0.0657)

where

X is the value to be standardised

Thus,

P(X ≥ 0.0657) = 1 - (520 - 518) / (180/√35)

= 1 - 0.0657

= 0.934

Therefore, the probability that a sample of the 35 exams will have a mean score of 518 or more is <em>0.934 or 93.4%</em>.

3 0

1 year ago

600 can be written as 2a x b x cd where a,b,c and d are all prime numbers find the values of a, b, c and d

mihalych1998 [28]

The prime factorisation of 600 is given by

$600 = 2 \times 2 \times 2 \times 3 \times 5 \times 5 = 2^3 \times 3 \times 5^2$

Therefore, a = 3, b = 3, c = 5 and d = 2.

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2 years ago

Match the following guess solutions ypyp for the method of undetermined coefficients with the second-order nonhomogeneous linear

Sunny_sXe [5.5K]

Answer:

Step-by-step explanation:

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For a non homogeneous part $- x^2 + x + 20$ , we assume the particular solution is

$y_p(x) = Ax^2 + Bx + C$

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For a non homogeneous part $e^{2x}$ , we assume the particular solution is

$y_p(x) = Ae^{2x}$

3 ) Given that

y′′ + 4y′ + 20y = −3sin(2x)

For a non homogeneous part −3sin(2x) , we assume the particular solution is

$y_p(x) = Acos(2x)+Bsin(2x)$

4 ) Given that

y′′ − 2y′ − 15y = 3xcos(2x)

For a non homogeneous part 3xcos(2x) , we assume the particular solution is

$y_p(x) = (Ax+B)cos2x+(Cx+D)sin2x$

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1 year ago

Which expression is equivalent to b^-2/ab^-3 assume a=0 b=0

andrey2020 [161]

B^-2/ab^-3 = b^-2/b^-3 x 1/a = b^[-2-(-3)] x 1/a = b x 1/a = b/a

3 0

1 year ago

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