Answer:
q(p)= -3000p+12000
Step-by-step explanation:
For the function to be linear,
q(p)= mp + c
where
q(p): number of hamburgers sold
p: price per hamburger
m: gradient of the function
c: constant of the function
q(p)=6000 when p=2
6000=2m+c .................... equation I
0=4m+c
c=-4m........................ equation II
Substitute value of c in equation I
6000=2m-4m
m= -3000
c=12000
q(p)= -3000p+12000
What was her starting average? 93 points
How much did her average increase or decrease, overall? 5 points
What was her final average? 83 points
Answer:
Option B.
Step-by-step explanation:
The given table of values is
x f(x)
-3 -2
-2 0
-1 2
0 2
1 0
2 -8
3 -10
4 -20
We need to find the interval for which the function f(x) is positive.
From the given table it is clear that the value of function f(x) is negative before -2 and after 1.
The function positive between x=-2 and x=1. So, we can conclude that the function f(x) is positive for the interval (-2,1).
Therefore, he correct option is B.
Answer:
Step-by-step explanation:
1. .....................................................................................................
A. This is a functional relationship as the number of workers depend on the number of job sites.
B. This is a functional relationship as the amount of money is dependent on the number of withdrawals
C. This is a functional relationship as the number of vitamins depend on the number of monkeys
D. This is NOT a functional relationship as the output is a fixed value. The performance and scoring may repeat.
2. .....................................................................................................
<h3>Given</h3>
<h3>To find </h3>
<h3>Solution</h3>
- A/B =
- (62x - 100)/(2x - 3) =
- (31*2x - 31*3 - 7)/(2x - 3) =
- (31(2x - 3) -7)/(2x - 3) =
- 31 - 7/(2x - 3)
Correct option is C.
Answer:
The answer is: C. $1407.50
Step-by-step explanation:
Buying:
30 * $20.95 + 20 * $25.50 =
$628.50 + $510 = $1138.
Selling:
50 * $28.75 = $1437.50
Remaining Cash:
$1437.50 - $30 = $1407.50
(This answer assumes Jen paid the other $30 per transaction when she bought the original shares, but had to pay $30 when she sold the shares.)