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Zepler [3.9K]
2 years ago
14

The triangle in the diagram represents a mold that Anna uses to shape dough before baking. Anna also has a circular mold whose r

im just fits inside the rim of the triangular mold. What is the radius of the circular mold?

Mathematics
2 answers:
ira [324]2 years ago
6 0

Answer:

5.35 cm

Step-by-step explanation:

It's correct on Plato.

My name is Ann [436]2 years ago
3 0
For the answer to the question above,
The triangle can be divided into 2 right triangles with 10 cm base, 18 cm hypotenuse. We need to find the measure of the long side to get the height of the isosceles triangle.

a² + b² = c² 
a² + (10cm)² = (18cm)² 
a² = 324 cm² - 100 cm²
a² = 224 cm²
a = √224 cm²
a = 14.97 cm

Area = 1/2 * base * height
A = 1/2 * 20 cm * 14.97 cm
A = 149.70 cm²

A = r/2 * p
149.70 cm² = r/2 * (18cm+18cm+20cm)
149.70 cm² = r/2 * 56 cm
149.70 cm² ÷ 56 cm = r/2
2.67 cm = r/2
2.67 cm * 2 = r
5.34 cm = r
So the answer to this question is
<span>5.35 cm is the radius</span>
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kadeem and quinn both drive 25 miles. Kadeem drives at a constant speed of 50 miles an hour. Quinn drives at a constant speed of
VARVARA [1.3K]

Answer:

Kadeem takes 10 minutes longer  to drive 25 miles.

Step-by-step explanation:

50m/hr = 25m/ half an hour

75m/hr = 25m/20 minutes

3 0
2 years ago
Find, correct to the nearest degree, the three angles of the triangle with the vertices d(0,1,1), e( 2, 4,3) − , and f(1, 2, 1)
Ksju [112]
Well, here's one way to do it at least... 

<span>For reference, let 'a' be the side opposite A (segment BC), 'b' be the side opposite B (segment AC) and 'c' be the side opposite C (segment AB). </span>

<span>Let P=(4,0) be the projection of B onto the x-axis. </span>
<span>Let Q=(-3,0) be the projection of C onto the x-axis. </span>

<span>Look at the angle QAC. It has tangent = 5/4 (do you see why?), so angle A is atan(5/4). </span>

<span>Likewise, angle PAB has tangent = 6/3 = 2, so angle PAB is atan(2). </span>

<span>Angle A, then, is 180 - atan(5/4) - atan(2) = 65.225. One down, two to go. </span>

<span>||b|| = sqrt(41) (use Pythagorian Theorum on triangle AQC) </span>
<span>||c|| = sqrt(45) (use Pythagorian Theorum on triangle APB) </span>

<span>Using the Law of Cosines... </span>
<span>||a||^2 = ||b||^2 + ||c||^2 - 2(||b||)(||c||)cos(A) </span>
<span>||a||^2 = 41 + 45 - 2(sqrt(41))(sqrt(45))(.4191) </span>
<span>||a||^2 = 86 - 36 </span>
<span>||a||^2 = 50 </span>
<span>||a|| = sqrt(50) </span>

<span>Now apply the Law of Sines to find the other two angles. </span>

<span>||b|| / sin(B) = ||a|| / sin(A) </span>
<span>sqrt(41) / sin(B) = sqrt(50) / .9080 </span>
<span>(.9080)sqrt(41) / sqrt(50) = sin(B) </span>
<span>.8222 = sin(B) </span>
<span>asin(.8222) = B </span>
<span>55.305 = B </span>

<span>Two down, one to go... </span>

<span>||c|| / sin(C) = ||a|| / sin(A) </span>
<span>sqrt(45) / sin(C) = sqrt(50) / .9080 </span>
<span>(.9080)sqrt(45) / sqrt(50) = sin(C) </span>
<span>.8614 = sin(C) </span>
<span>asin(.8614) = C </span>
<span>59.470 = C </span>

<span>So your three angles are: </span>

<span>A = 65.225 </span>
<span>B = 55.305 </span>
<span>C = 59.470 </span>
8 0
1 year ago
The necklace charm shown has two parts, each shaped like a trapezoid with identical dimensions. What is the total area, in squar
pashok25 [27]
The area of the trapezoid can be calculated through the equation, 
                               A = (b₁ + b₂)h / 2
where b₁ and b₂ are the bases and h is the height. Substituting the known values from the given, 
                              A = (25mm + 32mm)(15 mm) / 2 
                               A = 427.5 mm²
Since there are two trapezoids in the necklace, the area calculated is to be multiplied by two to get the total area. 
                        total area = (427.5 mm²)(2) 
                        <em>total area = 855 mm²</em>
3 0
2 years ago
Read 2 more answers
A cone-shaped pile of gravel has a diameter of 30 m and a height of 9.1 m.
Arte-miy333 [17]
D/2=r
vcone=(1/3)hpir^2
given
d=30
h=9.1
d/2=30/2=15=r

v=(1/3)9.1pi15^2
v=(9.1/3)pi225
v=682.5pi
use 3.141592 to aprox pi
v=2144.13654
the closese is the first one
answer would be 2120 m³
6 0
2 years ago
Read 2 more answers
In the expression " 5.3t - (20÷4) + 11" what part is a quotient? Describe its parts.​
enyata [817]

Answer:

(20 divided by 4) is the quotient

Step-by-step explanation:

4 0
2 years ago
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