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2 years ago

Carly and James share some money in the ratio 5 : 3

Mathematics

2 answers:

GalinKa [24]2 years ago

7 0

Answer:

£52

Step-by-step explanation:

let Carly shared is equal to 5x and it is equal to £70

then x is equal to 14

so James shared = 3x i.e. £52

Anni [7]2 years ago

3 0

Answer:

£42

Step-by-step explanation:

Let the money they share be x

Hence, 5:3 in the ratio Carly and James

Meaning Carly gets 5/ (5+3) × x = 5/8 x

But 5/8 x= £70

Meaning x = £70 × 8/5 = £112

But James gets 3/8 × x = 3/8 × £112

= £42

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Answer:

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Step-by-step explanation:

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markup = original cost * markup percent

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Answer:

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2 years ago

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Answer:

Option d.

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2 years ago

There are 345 students at a college who have taken a course in calculus, 212 who have taken a course in discrete mathematics, an

ollegr [7]

Answer:

369 students have taken a course in either calculus or discrete mathematics

Step-by-step explanation:

I am going to build the Venn's diagram of these values.

I am going to say that:

A is the number of students who have taken a course in calculus.

B is the number of students who have taken a course in discrete mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the number of students who have taken a course in calculus but not in discrete mathematics and $A \cap B$ is the number of students who have taken a course in both calculus and discrete mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

188 who have taken courses in both calculus and discrete mathematics.

This means that $A \cap B = 188$

212 who have taken a course in discrete mathematics

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4 0

2 years ago

What is the difference of the polynomials?(–2x3y2 + 4x2y3 – 3xy4) – (6x4y – 5x2y3 – y5)A–6x4y – 2x3y2 + 9x2y3 – 3xy4 + y5B–6x4y

saul85 [17]

We have to calculate the difference of the given polynomials, we follows as:

$(-2x^{3}y^{2}+4x^{2}y^{3}-3xy^{4})-(6x^{4}y-5x^{2}y^{3}-y^{5})$

After opening the brackets, the signs of all the terms changes as there is negative sign before the bracket.

= $(-2x^{3}y^{2}+4x^{2}y^{3}-3xy^{4})-6x^{4}y+5x^{2}y^{3}+y^{5})$

Combining all the like terms, we get as

= $(-2x^{3}y^{2})+(4x^{2}y^{3}+5x^{2}y^{3})-3xy^{4}-6x^{4}y+y^{5}$

= $-2x^{3}y^{2}+9x^{2}y^{3}-3xy^{4}-6x^{4}y+y^{5}$

Option A is the correct answer.

6 0

2 years ago

Read 2 more answers