Answer:
The set of numbers of the form 
, q≠0 and q≠ 1 or -1.
Step-by-step explanation:
We have that,
U = the universal set = the set of all rational numbers
S = set of all integers.
It is required to find 
.
Now, is the complement of the set S.
i.e. = U - S = set if rational numbers - set of integers
i.e. = the set of rationals which are not integers i.e. the set of points of the form , q≠0 and q≠ 1 or -1.
First, let's deal with the fraction in the denominator of the exponent. Multiply the top and bottom of the exponent by 6.
Now that the fraction in the denominator is taken care of, we can reduce the denominator.
. Some professors might accept this as simplest form, but others might ask you to get rid of the negative.
Answer:
160m/s
Step-by-step explanation:
The object can hit the ground when t = a; meaning that s(a) = s(t) = 0
So, 0 = -16a² + 400
16a² = 400
a² = 25
a = √25
a = 5 (positive 5 only because that's the only physical solution)
The instantaneous velocity is
v(a) = lim(t->a) [s(t) - s(a)]/[t-a)
Where s(t) = -16t² + 400
and s(a) = -16a² + 400
v(a) = Lim(t->a) [-16t² + 400 + 16a² - 400]/(t-a)
v(a) = Lim(t->a) (-16t² + 16a²)/(t-a)
v(a) = lim (t->a) -16(t² - a²)(t-a)
v(a) = -16lim t->a (t²-a²)(t-a)
v(a) = -16lim t->a (t-a)(t+a)/(t-a)
v(a) = -16lim t->a (t+a)
But a = t
So, we have
v(a) = -16lim t->a 2a
v(a) = -32lim t->a (a)
v(a) = -32 * 5
v(a) = -160
Velocity = 160m/s
