Ask question

Ask question

All categories

2 years ago

6

In yoshi's garden, 3/4 of the flowers are tulips. Of the tulips, 2/3 are yellow. What fraction of the flowers in Yoshi's garden

are yellow tulips?

1 answer:

sergiy2304 [10]2 years ago

3 0

The answer is 1/2. I hope i helped

You might be interested in

which of the following is equivalent to 3 sqrt 32x^3y^6 / 3 sqrt 2x^9y^2 where x is greater than or equal to 0 and y is greater

Nutka1998 [239]

Answer:

$\frac{\sqrt[3]{16y^4}}{x^2}$

Step-by-step explanation:

The options are missing; However, I'll simplify the given expression.

Given

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$

Required

Write Equivalent Expression

To solve this expression, we'll make use of laws of indices throughout.

From laws of indices $\sqrt[n]{a} = a^{\frac{1}{n}}$

So,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ gives

$\frac{(32x^3y^6)^{\frac{1}{3}}}{(2x^9y^2)^\frac{1}{3}}$

Also from laws of indices

$(ab)^n = a^nb^n$

So, the above expression can be further simplified to

$\frac{(32^\frac{1}{3}x^{3*\frac{1}{3}}y^{6*\frac{1}{3}})}{(2^\frac{1}{3}x^{9*\frac{1}{3}}y^{2*\frac{1}{3}})}$

Multiply the exponents gives

$\frac{(32^\frac{1}{3}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

Substitute $2^5$ for 32

$\frac{(2^{5*\frac{1}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$

From laws of indices

$\frac{a^m}{a^n} = a^{m-n}$

This law can be applied to the expression above;

$\frac{(2^{\frac{5}{3}}x*y^{2})}{(2^\frac{1}{3}x^{3}*y^{\frac{2}{3}})}$ becomes

$2^{\frac{5}{3}-\frac{1}{3}}x^{1-3}*y^{2-\frac{2}{3}}$

Solve exponents

$2^{\frac{5-1}{3}}*x^{-2}*y^{\frac{6-2}{3}}$

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$

From laws of indices,

$a^{-n} = \frac{1}{a^n}$ ; So,

$2^{\frac{4}{3}}*x^{-2}*y^{\frac{4}{3}}$ gives

$\frac{2^{\frac{4}{3}}*y^{\frac{4}{3}}}{x^2}$

The expression at the numerator can be combined to give

$\frac{(2y)^{\frac{4}{3}}}{x^2}$

Lastly, From laws of indices,

$a^{\frac{m}{n} = \sqrt[n]{a^m}$ ; So,

$\frac{(2y)^{\frac{4}{3}}}{x^2}$ becomes

$\frac{\sqrt[3]{(2y)}^{4}}{x^2}$

$\frac{\sqrt[3]{16y^4}}{x^2}$

Hence,

$\frac{\sqrt[3]{32x^3y^6}}{\sqrt[3]{2x^9y^2} }$ is equivalent to $\frac{\sqrt[3]{16y^4}}{x^2}$

8 0

2 years ago

What is the y-intercept of the polynomial f(x)f(x) f(x) defined below? Write the y-value only. f(x)=−4x2+x5+10x3+5x+8x4f(x)=-4x^

zhannawk [14.2K]

Answer:

y = 0

Step-by-step explanation:

Given

f(x) = 4x² +x⁵ +10x³ +5x+8x⁴

Required

Determine the y intercept

The y intercept of a function is a point where x = 0

So, we have to substitute 0 for x in the above function

f(x) = 4x² +x⁵ +10x³ +5x+8x⁴ becomes

f(0) = 4(0)² +(0)⁵ +10(0)³ +5(0)+8(0)⁴

f(0) = 4 * 0 + 0 + 10 * 0 + 5 * 0 + 8 * 0

f(0) = 0 + 0 + 0 + 0 + 0

f(0) = 0

Substitute y for f(0)

y = 0

Hence, the y intercept is 0

4 0

2 years ago

The scale of map is 4cm: 1km, the simplest possible ratio is a. 1cm: 250m b. 3cm: 560m c. 2cm: 340m

Zolol [24]

Answer:

1 cm : 250 m

Step-by-step explanation:

the scale is 4 cm : 1 km

4 cm/4 : 1 km/4

1 cm : 250 m

6 0

2 years ago

Read 2 more answers

Daniel wants to predict how far he can hike based on the time he spends on the hike. He collected some data on

horsena [70]

Answer:

Daniel can read his data and refer to line as best line of fit and estimate an average per set of hours.

Step-by-step explanation:

A line of fit draws a solid conclusion to the average for the hours spent during the amount of indicated hours. We draw a line of fit central fit and aim similar centrality as that similar results of the mean (without working out the mean we can draw a line perpendicular to the number of mean, but in line of fit we go central to all the descending or cascading results to include all results but just using one line), with one further consideration and that is balance if anything sticks out from the norm ie) weather conditions including data, we suggest if there is nothing to weigh the line of fit to a balancing outcome that shows the opposite of kilometres walked (eg. extreme higher mileage within the hour/s) then it may just alter the line a fraction of how many treks he did, but not in data less than 30 entries. Have attached an example where they classify in economics something outside the norm is called a misfit. Daniel can read his data and refer to line as best line of fit and estimate an average per set of hours. Here on the attachment you can read any misfit info and use the line coordination perpendicular to guide the indifference, the attachment shows it is not really included in the best line of fit as other dominating balances have occurred and therefore we have a misfit, all whilst using best line of fit to balance everything fairly.

7 0

2 years ago

Read 2 more answers

A square rotated about its center by 360º maps onto itself at(1,2,3,4) different angles of rotation. You can reflect a square on

Sladkaya [172]

A square rotated about its center by 360º maps onto itself at 90°, 180°, 270° and 360° - 4 different angles of rotation.

You can reflect a square onto itself across two diagonals and two segments that connects the middlepoints of opposite sides - 4 different lines of reflection.

7 0

2 years ago