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2 years ago

6

In yoshi's garden, 3/4 of the flowers are tulips. Of the tulips, 2/3 are yellow. What fraction of the flowers in Yoshi's garden

are yellow tulips?

1 answer:

sergiy2304 [10]2 years ago

3 0

The answer is 1/2. I hope i helped

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Find the length of the third side of the right triangle.

lara31 [8.8K]

Answer: you can use Pythagorean theorem , which formula is $a^{2} + b^{2} =c^{2}$ , "a" and "b" are the sides, and "c" is the hypotenuse (the longest side, the side opposite to the 90 degree angle)

<em>Example:</em>

If they give that one side is 2 inches and the other side is 4 and you need to find the hypotenuse it would be like this:

1) plug the numbers to the formula

$4^2 + 6^2 = c^{2}$

2) solve the exponents of the numbers given (not the letter, in this case "c")

16 + 36 = $c^2$

3) combine like terms (in this case 16 +36)

52 = $c^2$

4) Finally, Find the square root of "c" to remove its exponent and do the same to the other side, in this case 52)

$\sqrt{52} = \sqrt{c}$

(square root of 52 rounded to the nearest hundred is 7.21)

7.21 = c

<h3><u><em>So 7.21 is your missing side in this example</em></u></h3><h3>look up Pythagorean theorem Khan Academy</h3>

8 0

2 years ago

A study of immunizations among school‑age children in California found that some areas had rates of unvaccinated school‑age chil

Rom4ik [11]

Answer:

Probability that none of the 20 children in such a classroom would be unvaccinated is 0.055.

Step-by-step explanation:

We are given that a classroom of 20 children in one such area where 13.5% of children are unvaccinated.

If there are no siblings in the classroom, we are willing to consider the vaccination status of the 2020 unrelated children to be independent.

The above situation can be represented through binomial distribution;

$P(X=r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r} ; x = 0,1,2,3,......$

where, n = number of trials (samples) taken = 20 children

r = number of success = none of the 20 children

p = probability of success which in our case is probability that

children are unvaccinated, i.e; p = 13.5%

<u><em>Let X = Number of children that are unvaccinated</em></u>

So, X ~ Binom(n = 20, p = 0.135)

Now, Probability that none of the 20 children in such a classroom would be unvaccinated is given by = P(X = 0)

P(X = 0) = $\binom{20}{0} \times 0.135^{0} \times (1-0.135)^{20-0}$

= $1\times 1 \times 0.865^{20}$

= 0.055

<em>Hence, the probability that none of the 20 children in such a classroom would be unvaccinated is 0.055.</em>

8 0

2 years ago

Rachael ordered early learning software for her daughter from an online retailer. Each item costs $6.50, and there is a shipping

natta225 [31]

Answer:

Step-by-step explanation:

(a)

Total cost = (7 items * Cost per item) + Shipping fee = 7*6.5 + 8.5 = $54

(b)

Modelling the above equation with symbols:

c = s*6.5 + 8.5 = 6.5s + 8.5

(c)

For a total cost of 80$, c = 80:

80 = 6.5s + 8.5

Calculating, we get:

s = 11 items

Rachel ordered a total of 11 items

4 0

2 years ago

Read 2 more answers

If X is a normal random variable with parameters µ = 10 and σ 2 = 36, compute

alex41 [277]

Answer:

Step-by-step explanation:

Given that X is a normal random variable with parameters µ = 10 and σ 2 = 36,

X is N(10, 6)

Or z = $\frac{x-10}{6}$

is N(0,1)

a) P(X > 5),

= $P(Z>-0.8333)\\=0.7977$

(b) P(4 < X < 16),

= $P(|z|$

(c) P(X < 8),

= $P(Z$

(d) P(X < 20),

= $P(Z$

(e) P(X > 16).

=P(Z>-0.6667)

= 0.2524

6 0

2 years ago

What is the mixed number to 53/12

Virty [35]

The mixed number is 4 5/12.

6 0

2 years ago