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FromTheMoon [43]
2 years ago
9

If the pressure inside a rubber balloon is 1500 mmHg, what is this pressure in pounds-force per square inch (psi)? Answer: 29.0

psi
Mathematics
1 answer:
vivado [14]2 years ago
5 0

Answer:

Pressure magnitude of 1500 mmHg equals 29.00 pounds per square inch.

Step-by-step explanation:

We know that 1 mmHg of pressure equals 0.0193368 psi

Thus the value of 1500 mmHg pressure in psi can be found by proportion as

1500mmHg=1500mmHg\times \frac{0.0193368psi}{mmHg}\\\\\therefore 1500mmHg=29.00psi

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Un globo busca aterrizar en medio de dos ciudades A y B, cuya distancia entre si es de 200 km. Si se mide el ángulo de elevación
scoundrel [369]

Answer:

h \approx 59.898\,km

Step-by-step explanation:

El diagrama trigonométrico que representa el enunciado es incluido abajo como adjunto. Las siguientes relaciones trigonométricas describen la localización del globo. (The trigonometric diagram representing the statement is included below as attachment. The following trigonometric relations describes the location of the balloon):

\tan 27^{\circ} = \frac{h}{x}

\tan 36^{\circ} = \frac{h}{200-x}

A continuación, se obtiene la distancia horizontal: (The horizontal distance is obtained hereafter):

x \cdot \tan 27^{\circ} = (200-x)\cdot \tan 36^{\circ}

x \cdot (\tan 27^{\circ} + \tan 36^{\circ})= 200\cdot \tan 36^{\circ}

x = \frac{200\cdot \tan 36^{\circ}}{\tan 27^{\circ}+ \tan 36^{\circ}}

x \approx 117.557\,km

La altura aproximada del globo es (The approximated height of the globe is):

h = x\cdot \tan 27^{\circ}

h \approx 59.898\,km

7 0
2 years ago
The measure of ∠1 =<br><br> 55<br> 62.5<br> 110
elena-s [515]
360 - 250 = 110
m<1 = 110/2 = 55

answer
55
8 0
2 years ago
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Tommy has a piece of toast that has butter on one side, and he dropped it twice. Both times, it landed with the butter side up.
Shkiper50 [21]
Since probability is the measure of the likelihood that an event will occur.so, maybe 5.
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Evaluate 6+3b if b=7
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27. Replace b with 7, making 6 + 3(7). The 3 and parentheses of 7 hint multiplication, so you multiply to make 21, then add 6 relating back to PEMDAS to teach you the correct order to solve the problem.
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A has the coordinates (–4, 3) and B has the coordinates (4, 4). If DO,1/2(x, y) is a dilation of △ABC, what is true about the im
loris [4]

Answer:

Coordinates of Vertices of triangle ABC are A (-4,3) , B(4,4) and C(1,1).

As, DO is Dilation of Δ ABC by Scale factor of \frac{1}{2}.

Vertices of A' B'C' are

A'=(\frac{-4}{2},\frac{3}{2})=(-2,\frac{3}{2}), B'=(\frac{4}{2},\frac{4}{2})=(2,2), C'=(\frac{1}{2},\frac{1}{2})

So, Image Δ A'B'C' will be smaller than the Pre image Δ ABC.

The two triangles will be congruent.

AO is Dilated by a factor of half , so A'O' will be half of AO.

So, correct Statements are

1. AB is parallel to A'B'.

2.DO,1/2(x, y) =  

The distance from A' to the origin is half the distance from A to the origin.

OA=\sqrt{(-4)^2+3^2}=\sqrt{25}=5\\\\ O'A'=\sqrt{2^2+(\frac{3}{2})^2}=\frac{5}{2}=2.5

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