Answer:
67
Step-by-step explanation:
Division:-
Wendy is paid $12 per hour and plans to work between 30 and 35 hours per week. Identify the independent and dependent quantity i
2 answers:
Answer:
Independent quantity = Number of hours
Dependent quantity = Wendy's salary
Domain = [30,35]
Range = [360,420]
Step-by-step explanation:
Dependent variable: If the value of one variable is dependent on another variable, then it is called dependent variable.
Independent variable: If the value of one variable is not dependent on another variable, then it is called independent variable.
It is given that Wendy is paid $12 per hour and plans to work between 30 and 35 hours per week.
In this case Wendy's salary is dependent on number of working hours. So, number of hours is independent and Wendy's salary is dependent quantity.
Let y be the total earning of Wendy in x hours.
Wendy is paid $12 per hour. So the Wendy's salary is defined by the equation
Domain is the set of inputs or x values.
Range is the set of outputs or y-values.
She plans to work between 30 and 35 hours per week. So, the reasonable domain is
Domain = 30 ≤ x ≤ 35 = [30,35]
At x=30,
At x=35,
So, the reasonable Range is
Range = 360 ≤ y ≤ 420 = [360,420]
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Answer:
January had a higher z-score for sales on the 15th, and the value of that z-score was of 0.5.
Step-by-step explanation:
z-score:
In a set with mean and standard deviation
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
January:
The mean daily sales for January was $300 with a standard deviation of $20. On the 15th of January, the shop sold $310 of yogurt. This means, respectively, that . So
February:
The mean daily sales for February was $320 with a standard deviation of $50. On the 15th of February, the shop sold $340 of yogurt. This means, respectively, that . So
January had a higher z-score for sales on the 15th, and the value of that z-score was of 0.5.
Answer:
1) The probability that ten students in a class have different birthdays is 0.883.
2) The probability that among ten students in a class, at least two of them share a birthday is 0.002.
Step-by-step explanation:
Given : Assume there are 365 days in a year.
To find : 1) What is the probability that ten students in a class have different birthdays?
2) What is the probability that among ten students in a class, at least two of them share a birthday?
Solution :
Total outcome = 365
1) Probability that ten students in a class have different birthdays is
The first student can have the birthday on any of the 365 days, the second one only 364/365 and so on...
The probability that ten students in a class have different birthdays is 0.883.
2) The probability that among ten students in a class, at least two of them share a birthday
P(2 born on same day) = 1- P( 2 not born on same day)
The probability that among ten students in a class, at least two of them share a birthday is 0.002.