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lesya [120]
2 years ago
13

a net force of 15 N is exerted on an encyclopedia to cause it to accelerate at a rate of 5 m/s². determine the mass of the encyc

lopedia
Mathematics
1 answer:
Aloiza [94]2 years ago
6 0
We take 15 N divided by 5m/s2 because m/s2 is equal to N/kg. So, the answer is 3kg. Its what i think
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A candy maker estimated that she had 2500 bags of candy. She had put prizes in 92 of them. She collected a sample in which there
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2 years ago
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David bought a baseball card for $40. the value of the card increased by 25%. what is the new value of the card?
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Step-by-step explanation:

5 0
2 years ago
Which summation represents the total number of pennies on the chessboard?
Charra [1.4K]

Answer:

  • First option of the figure:

                                                      \sum_{n=1}^{64}1.2^{n-1}

Explanation:

Assume that the complete question includes the following description of how the pennies are placed on the chessboard:

"If a chessboard (8×8) were to have pennies placed on each square such that 1 penny was placed on the first square, 2 on the second, 4 on the third, and so on (doubling the number of pennies on each subsequent square), how many pennies would be on the chessboard when finished?"

From that you can write the first terms of the sequence that represent such description

Square           number of pennies         power form

   1                                 1                           1 × 2⁰

  2                                2                           1 × 2¹

  3                                4                           1 × 2²

  4                                8                          1 × 2³

  5                               16                          1 × 2⁴

  n                                                             1 × 2ⁿ⁻¹

  64                                                           1 × 2⁶³

Hence, you to have the total number of pennies you have to sum the number of pennies on every square of the chessboard, which will lead to :

1 × 2⁰ +  1 × 2¹ + 1 × 2² +  1 × 2³ +  1 × 2⁴ + ...  1 × 2ⁿ⁻¹ up to n = 64 or n - 1 = 63.

That is the sum from n = 1 to 64 - 1 of 1 × 2ⁿ⁻¹, which using summation form is the first option on the picture.

                 \sum_{n=1}^{64}1.2^{n-1}

4 0
2 years ago
Read 2 more answers
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