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tatiyna
2 years ago
13

On a map of the united states , 24 centimeters represent 18 miles .how many centimeters reprsent one mile. How long is the line

segment between A and B in centimeters? If A and B represent 2 cities what is the actual distance between the two cities
Mathematics
1 answer:
VladimirAG [237]2 years ago
3 0
1.33 equals one mile and 24 centimeters. Also 18 miles is the actual distance. I hope this helped but i was a little confused but i am pretty sure the answers are right
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The cost of producing x soccer balls in thousands of dollars is represented by h(x) = 5x + 6. The revenue is represented by
Firdavs [7]

Answer:

(k-h)(x) = 4x - 8

Step-by-step explanation:

We know Profit = Revenue - Cost

Basically we gotta subtract cost function from revenue function and get the profit function.

The cost function is h(x) = 5x + 6

The revenue function is k(x) = 9x - 2

Hence, Profit is:

(k-h)(x) = (9x - 2) - (5x + 6)

(k-h)(x) = 9x -2 - 5x - 6

(k-h)(x) = 4x - 8

3 0
2 years ago
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Which point is a solution to the inequality shown in this graph?
Hitman42 [59]
Ur answer is (0,-3)

because ur line is a solid line, this means any number on that line is a solution....along with any points that are in the blue area. when u plot ur answer choices, if it falls in the white area, it is not a solution
7 0
2 years ago
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An urn contains two blue balls (denoted B1 and B2) and three white balls (denoted W1, W2, and W3). One ball is drawn, its color
alekssr [168]

Answer:

(a) Shown below.

(b) The probability that the first ball drawn is blue is 0.40.

(c) The probability that only white balls are drawn is 0.36.

Step-by-step explanation:

The balls in the urn are as follows:

Blue balls: B₁ and B₂

White balls: W₁, W₂ and W₃

It is provided that two balls are drawn from the urn, with replacement, and their color is recorded.

(a)

The possible outcomes of selecting two balls are as follows:

B₁B₁          B₂B₁          W₁B₁          W₂B₁          W₃B₁

B₁B₂         B₂B₂          W₁B₂         W₂B₂          W₃B₂

B₁W₁         B₂W₁         W₁W₁         W₂W₁         W₃W₁

B₁W₂        B₂W₂         W₁W₂        W₂W₂         W₃W₂

B₁W₃        B₂W₃         W₁W₃        W₂W₃         W₃W₃

There are a total of N = 25 possible outcomes.

(b)

The sample space for selecting a blue ball first is:

S = {B₁B₁, B₁B₂, B₁W₁, B₁W₂, B₁W₃, B₂B₁, B₂B₂, B₂W₁, B₂W₂, B₂W₃}

n (S) = 10

Compute the probability that the first ball drawn is blue as follows:

P(\text{First ball is Blue})=\frac{n(S)}{N}=\frac{10}{25}=0.40

Thus, the probability that the first ball drawn is blue is 0.40.

(c)

The sample space for selecting only white balls is:

X = {W₁W₁, W₂W₁, W₃W₁, W₁W₂, W₂W₂, W₃W₂, W₁W₃, W₂W₃, W₃W₃}

n (X) = 9

Compute the probability that only white balls are drawn as follows:

P(\text{Only White balls})=\frac{n(X)}{N}=\frac{9}{25}=0.36

Thus, the probability that only white balls are drawn is 0.36.

4 0
2 years ago
Write the ratio as a fraction in simplest form: 2.35 to 5.25.
Sliva [168]

Step-by-step explanation:

\frac{2.35}{5.25}  =  \frac{235}{525}  =  \frac{47}{105}  = 47 \:  : \: 105 \\

4 0
2 years ago
contractor wishes to build 9 houses, each different in design. In how many ways can he place these houses on a street if 6 lots
Tju [1.3M]

The houses can be placed in 362,880 ways.

<u>Step-by-step explanation:</u>

The 9 houses are each in different design.

The each lot can place any of the 9 houses.

  • The 1st lot can place anyone house of all the 9 houses.
  • The 2nd lot can place one of remaining 8 houses.
  • The 3rd lot can place one of remaining 7 houses.

Similarly, the process gets repeated until the last house is placed on a lot.

<u>From the above steps, it can be determined that :</u>

The number of ways to place the 9 houses in 9 lots = 9!

⇒ 9×8×7×6×5×4×3×2×1

⇒ 362880 ways.

Therefore, the houses can be placed in 362880 ways.

5 0
2 years ago
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