Answer:
sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x
Step-by-step explanation:
From the given triangle JKL;
Hypotenuse KJ = 10.9
Length LJ is the opposite = 8.9cm
The angle LKJ is the angle opposite to side KJ = x
Using the SOH CAH TOA Identity;
sin theta = opp/hyp
sin LKJ = LJ/KJ
Sinx = 8.9/10.9
x = arcsin(8.9/10.9)
sin−1(StartFraction 8.9 Over 10.9 EndFraction) = x
Step 1 (simplify):
3+5x(2-1)
8 x 1
Step 2 (solve):
8 x 1 = 8
8 is your answer. Hope this helps :)
Answer: h=25+m
Twenty five minutes of reading plus the math.
Complete the table? There is no table shown, but just add 25 to the values of m given to get h values, or take away 25 for given hs to get ms.
