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2 years ago

Simplify the following expression 3^0

Mathematics

1 answer:

Gennadij [26K]2 years ago

5 0

Answer:

Step-by-step explanation:

Any real number to the power of 0 is one (being that there is always a denominator of 1).

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Mr. Peterson needs topsoil for his garden. His rectangular garden is 78 in long and 48 in wide. A bag of topsoil covers an area

nata0808 [166]

Answer:

3744 inches squared, and 8 bags

Step-by-step explanation:

Ⓗⓘ ⓣⓗⓔⓡⓔ

˜”*°•.˜”*°• Area: •°*”˜.•°*”˜

Well, the formula for area is L*W

L=78 inches

W=48 inches

78*48=3744 inches squared

˜”*°•.˜”*°• Number of bags: •°*”˜.•°*”˜

3744/500=7.448

So he would need to buy 8 bags

(っ◔◡◔)っ ♥ Hope this helped! Have a great day! :) ♥

4 0

2 years ago

If m< LMP is 11 degrees more than m< NMP and m< NML =137, find each measure

Agata [3.3K]

First, note that for angles LMP and NMP you have

$m\angle LMP+m\angle NMP=m\angle NML.$

If $m\angle LMP$ is $11^{\circ}$ more than $m\angle MNP,$ then

$m\angle LMP=m\angle NMP+11^{\circ}.$

Now, since $m\angle MNL=137^{\circ},$ you have

$137^{\circ}=m\angle NMP+11^{\circ}+m\angle NMP,\\ \\2m\angle NMP=137^{\circ}-11^{\circ}=126^{\circ},\\ \\m\angle NMP=63^{\circ}.$

Therefore,

$m\angle LMP=63^{\circ}+11^{\circ}=74^{\circ}.$

Answer: $m\angle LMP=74^{\circ},\ m\angle NMP=63^{\circ}.$

7 0

2 years ago

The annual salaries of all employees at a financial company are normally distributed with a mean of $34,000 and a standard devia

Alla [95]

Answer:

$z=5$

Step-by-step explanation:

We have been given that the The annual salaries of all employees at a financial company are normally distributed with a mean of $34,000 and a standard deviation of $4,000.

To solve our given problem we will use z-score formula.

$z=\frac{x-\mu}{\sigma}$ where,

$z=\text{z-score}$ ,

$x=\text{Sample score}$ ,

$\mu=\text{Mean}$ ,

$\sigma=\text{Standard deviation}$

Upon substituting our given values in z-score formula we will get,

$z=\frac{54,000-34,000}{4,000}$

$z=\frac{20,000}{4000}$

$z=5$

Therefore, the z-score of a company employee who makes an annual salary of $54,000 is 5.

4 0

2 years ago

Read 2 more answers

Suppose a marketing company computed a 94% confidence interval for the true proportion of customers who click on ads on their sm

Ksivusya [100]

Answer:

d. There is a 98% chance that the true proportion of customers who click on ads on their smartphones is between 0.56 and 0.62.

Step-by-step explanation:

Confidence interval:

x% confidence

Of a sample

Between a and b.

Interpretation: We are x% sure(or there is a x% probability/chance) that the population mean is between a and b.

In this question:

I suppose(due to the options) there was a small typing mistake, and we have a 98% confidence interval between 0.56 and 0.62.

Interpreation: We are 98% sure, or there is a 98% chance, that the true population proportion of customers who click on ads on their smartphones is between 0.56 and 0.62. Option d.

3 0

2 years ago

77 million to 200.2 million

Luda [366]

77 million to 200.2 millionFrom 77 million it becomes 200.2 million.It is very noticeable that it increased we only need to identify the number that has increased.=> 200.2 - 77 million = 123.2 millionNow, let's find the increase rate:=> 123.2 million / 200.2 million = 0.62Now let's convert this to percentage=> 0.62 * 100% = 62%<span>
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4 0

2 years ago