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2 years ago

77 million to 200.2 million

1 answer:

4 0

77 million to 200.2 millionFrom 77 million it becomes 200.2 million.It is very noticeable that it increased we only need to identify the number that has increased.=> 200.2 - 77 million = 123.2 millionNow, let's find the increase rate:=> 123.2 million / 200.2 million = 0.62Now let's convert this to percentage=> 0.62 * 100% = 62%<span>
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A line passes through the points (p, a) and (p, –a) where p and a are real numbers and p ≠ 0. Describe each of the following. Ex

MissTica

Answer:

Part A) The slope is undefined

Part B) The equation of the line is $x=p$

Part C) None y-intercept

Part D) The slope of a line perpendicular to the given line is equal to zero

Step-by-step explanation:

we have that

Describe

A) slope of the line

B) equation of the line

C) y-intercept

D) slope of a line perpendicular to the given line

Part A) slope of the line

we know that

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

$(p,a)\ (p,-a)$

Substitute the values

$m=\frac{-a-a}{p-p}$

$m=\frac{-2a}{0}$ -----> the slope is undefined

Its a vertical line (parallel to the y-axis)

Part B) Equation of the line

we know that

The equation of a vertical line is equal to the x-coordinate of the points through which the line passes.

$x=p$

Part C) The y-intercept

The y-intercept is the value of y when the value of x is equal to zero

The vertical line not intercept the y-axis

None y-intercept

Part D) slope of a line perpendicular to the given line

A line perpendicular to the given line is a horizontal line (parallel to the x-axis)

therefore

The slope is equal to zero

6 0

2 years ago

Elias and Niko are polishing the silver at the heritage museum.Elias could polish all the silver himself in 40 minutes.That task

irina1246 [14]

Let x be the time it takes Elias and Niko to polish the silver working together. If Elias works alone, he could polish all the silver himself in 40 minutes. Then, in 1 minute, he will make $\frac{1}{40}$ of the total work. If the same analysis is applied Niko, in 1 minute, will make $\frac{1}{50}$ of the total work.

Working together Elias and Niko will need x minutes to make all the work. Then, in 1 minute, they will make $\frac{1}{x}$ of the total work. So, the fraction of the total work they make in 1 minute is given by this equation:

$\frac{1}{x}=\frac{1}{40}+\frac{1}{50} \\ \\ \frac{1}{x}=\frac{50+40}{2000} \\ \\ x=\frac{2000}{90} \\ \\ \boxed{x=22.22 minutes}$

6 0

2 years ago

Read 2 more answers

Given p ≠ q ≠ 0, what is the equation of the line that passes through the points (–p, –q) and (p, q)?

liubo4ka [24]

Hey :))

(-p,-q)(p,q)slope = (q - (-q) / (p - (-p) = (q + q) / (p + p) = 2q / 2p = q/p
y = mx + b.....slope(m) = q/p(p,q)...x = p and y = qnow we sub and find b, the y intq = (q/p)(p) + bq = q + bq - q = b0 = b
so ur equation is : y = (q/p)x + 0...or just y = (q/p)x....its answer B
HOPE THIS HELPED!!! :))

7 0

2 years ago

Read 2 more answers

Performance task: A parade route must start And and at the intersections shown on the map. The city requires that the total dist

GaryK [48]

Answer:

Part A: The proposed route does not meet requirement because it is longer than the maximum required length of 3 miles

Part B: For the total distance is as close to 3 miles as possible, the start point of the parade should be at the point on Broadway with coordinates (9.941, 4.970)

Part C: The coordinates of the cameras stationed half way down each road are;

For central avenue; (4, 2)

For Broadway; (7.97, 2.49)

Step-by-step explanation:

Part A: The length of the given route can be found using the equation for the distance, l, between coordinate points as follows;

$l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}$

Where for the Broadway potion of the parade route, we have;

(x₁, y₁) = (12, 3)

(x₂, y₂) = (6, 0)

$l_1 = \sqrt{\left (0 -3\right )^{2}+\left (6-12 \right )^{2}} = 3 \cdot \sqrt{5}$

For the Central Avenue potion of the parade route, we have;

(x₁, y₁) = (6, 0)

(x₂, y₂) = (2, 4)

$l_2 = \sqrt{\left (4 -0\right )^{2}+\left (2-6 \right )^{2}} = 4 \cdot \sqrt{2}$

Therefore, the total length of the parade route =-3·√5 + 4·√2 = 12.265 unit

The scale of the drawing is 1 unit = 0.25 miles

Therefore;

The actual length of the initial parade =0.25×12.265 unit = 3.09 miles

The proposed route does not meet requirement because it is longer than the maximum required length of 3 miles

Part B:

For an actual length of 3 miles, the length on the scale drawing should be given as follows;

1 unit = 0.25 miles

0.25 miles = 1 unit

1 mile = 1 unit/(0.25) = 4 units

3 miles = 3 × 4 units = 12 units

With the same end point and route, we have;

$l_1 = \sqrt{\left (0 -y\right )^{2}+\left (6-x \right )^{2}} = 12 - 4 \cdot \sqrt{2}$

y² + (6 - x)² = 176 - 96·√2

y² = 176 - 96·√2 - (6 - x)²............(1)

Also, the gradient of l₁ = (3 - 0)/(12 - 6) = 1/2

Which gives;

y/x = 1/2

y = x/2 ..............................(2)

Equating equation (1) to (2) gives;

176 - 96·√2 - (6 - x)² = (x/2)²

176 - 96·√2 - (6 - x)² - (x/2)²= 0

176 - 96·√2 - (1.25·x²- 12·x+36) = 0

Solving using a graphing calculator, gives;

(x - 9.941)(x + 0.341) = 0

Therefore;

x ≈ 9.941 or x = -0.341

Since l₁ is required to be 12 - 4·√2, we have and positive, we have;

x ≈ 9.941 and y = x/2 ≈ 9.941/2 = 4.97

Therefore, the start point of the parade should be the point (9.941, 4.970) on Broadway so that the total distance is as close to 3 miles as possible

Part C: The coordinates of the cameras stationed half way down each road are;

For central avenue;

Camera location = ((6 + 2)/2, (4 + 0)/2) = (4, 2)

For Broadway;

Camera location = ((6 + 9.941)/2, (0 + 4.970)/2) = (7.97, 2.49).

5 0

2 years ago

Q is in the interior of angle ROS S in the interior of angle QOP. P is in the interior of angle SOR. S is in the interior of ang

MrMuchimi

∠ROT=160°

∠SOT=100°

Now ∠SOR= ∠ROT - ∠SOT

∠ SOR = 160°-100°

∠ SOR =60°

It is given that measure of angle ROQ to equals the measure of angle QOS equals the measure of angle POT.

∠SOQ + ∠QOR = 60°

But ∠SOQ = ∠QOR

2∠SOQ=60°

∠SOQ=60°÷2

∠SOQ =30°

Also ∠POT=∠SOQ=∠ROQ=30°

3 0

2 years ago