Elaine is in London for one day only. She only has time to see two shows of the three shows she likes. The shows are Hamilton, A
1 answer:
Answer:
Step-by-step explanation:
All three shows she likes are Hamilton, Aladdin, and Thriller.
But she can watch only two shows among the three shown.
The possible combination of the shows she can watch are
(Hamilton and Aladdin), (Aladdin and Thriller) and (Hamilton and Thriller).
So, the total number of possible events (available options)= 3.
As we have to determine the probability of watching Aladdin and Thriller, so here Aladdin and Thriller is the favorable event.
So, the number of favorable event=1
Now,
Hence, the probability that she sees Aladdin and Thriller is .
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Answer:
Step-by-step explanation:
Hello!
The variable is X: iron level on human blood.
It has a mean of μ= 51.50 mg/dl and a standard deviation of σ= 3.50 mg/dl.
According to the control chart, the process should be shut down for troubleshooting when the analysis shows values X[bar]≥ 53.42 mg/dl and X[bar]≤ 49.58 mg/dl
Warnings are received at levels X[bar]≥52.78 mg/dl and X[bar]≤ 50.22 mg/dl
The system works between levels 49.58<X[bar]<53.42 and works without warnings between 50.22<X[bar]<52.78.
Using these parameters you have to analyze if the lists of sample means to see which ones are within the working values are wich ones are outside this interval.
<u>Sample 1</u>
Min= 50.15
Max= 51.99
Mean= 51.61
Without warning 50.22<X[bar]<52.78
Without Action interval 49.58<X[bar]<53.42
<em>This sample's min value is below the lower limit of the warning interval but not low enough to reach action levels, the max value is within the working range.</em>
<em><u /></em>
<u>Sample 2 </u>
Min= 50.32
Max= 52.56
Mean= 51.16
Without warning 50.22<X[bar]<52.78
Without Action interval 49.58<X[bar]<53.42
<em>Both the max and min values of the sample are within the working range without warning.</em>
<em />
<u>Sample 3</u>
Min= 50.25
Max= 53.12
Mean= 51.83
Without warning 50.22<X[bar]<52.78
Without Action interval 49.58<X[bar]<53.42
<em>The max value of this sample is above the upper limit of the warning interval but does not surpass the upper bond of the troubleshoot interval. Min value is within working values.</em>
<em />
<u>Sample 4</u>
Min= 50.05
Max= 53.01
Mean= 51.70
Without warning 50.22<X[bar]<52.78
Without Action interval 49.58<X[bar]<53.42
<em>Both min and max values surpass the warning interval but do not reach action levels</em>.
<u>Sample 5</u>
Min= 50.35
Max= 52.71
Mean= 51.37
Without warning 50.22<X[bar]<52.78
Without Action interval 49.58<X[bar]<53.42
<em>Both min and max values are within working levels without warnings.</em>
<em />
Considering that samples reaching warning levels should be shut down as a precaution, they are classified as:
Shutdown: Sample 1, 3 and 4
Do not shutdown: Sample 2 and 5.
I hope it helps!
<u>Answer:</u>
There are two approaches to solving the equation -3x + 10 = 4x - 20. The value of x after solving in both methods is 4.2857.
<u>Solution:</u>
Given, equation is -3x + 10 = 4x – 20.
We have to solve the given equation in two methods, now let us see the first method.
<u><em>1st method ⇒ by subtracting 4x from both sides.</em></u>
Then, -3x + 10 = 4x – 20 ⇒ -3x + 10 – 4x = 4x – 20 – 4x ⇒ -3x – 4x = -20 – 10 ⇒ -7x = -30 ⇒ 7x = 30
Then, x =
Now, let us use the 2nd method.
<em><u>2nd method ⇒ by adding 3x on both sides.</u></em>
Then, -3x + 10 = 4x – 20 ⇒ -3x + 10 + 3x = 4x – 20 + 3x
⇒ 10 + 20 = 4x + 3x
⇒ 7x = 30
⇒ x =
Hence, the value of x after solving in both methods is = 4.2857.