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Tanzania [10]
2 years ago
13

On a coordinate plane, a cube root function goes through (negative 2.5, negative 3.5), crosses the y-axis at (0, negative 3), ha

s an inflection point at (1, negative 2), and goes through (2, negative 1). Determine the values of h and k in the equation of g(x). G(x) = RootIndex 3 StartRoot x minus h EndRoot+ k h = k =

Mathematics
1 answer:
mart [117]2 years ago
4 0

Answer:

g(x) = \sqrt[3]{x-1} - 2

Step-by-step explanation:

We want to find h and k in:

g(x) = \sqrt[3]{x-h} + k

At the inflection point, the second derivative is equal to zero, so:

g'(x) = \frac{1}{3} (x-h)^{\frac{-2}{3}}

g''(x) = \frac{1}{3} \frac{-2}{3}(x-h)^{\frac{-5}{3}} = 0

Then x - h = 0.

Inflection point is located at (1, -2), replacing this x value we get:

1 - h = 0

h = 1

We know that the point (-2.5, -3.5) belongs to the function, so:

-3.5 = \sqrt[3]{-2.5-1} + k

k ≈ -2

All data, used or not, are shown in the picture attached.

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I WILL GIVE BRAINLIEST Draw the line of reflection that reflects △ABC\triangle ABC△ABCtriangle, A, B, C onto △A′B′C′\triangle A'
Bogdan [553]

Answer:

See diagram attached.

Step-by-step explanation:

The line of reflection of preimage ABC reflected onto image A'B'C' can be found by the perpendicular bisector of lines joining the corresponding points of the image and preimage, for example, AA', or BB'.

See diagram attached.

3 0
2 years ago
Triangle PQR with vertices P(3, −6), Q(6, −9), and R(−15, 3) is dilated by a scale factor of 3 to obtain triangle P′Q′R′. Which
vovangra [49]

Answer:

Option C.

Step-by-step explanation:

The vertices of triangle PQR are P(3, −6), Q(6, −9), and R(−15, 3).

It is given that triangle PQR dilated by a scale factor of 3 to obtain triangle P′Q′R′.

We know that a figure and its image after dilation are similar. It means triangle PQR and triangle P′Q′R′

If a figure dilated by factor k about the origin then

(x,y)\rightarrow (kx,ky)

PQR dilated by a scale factor of 3, so

(x,y)\rightarrow (3x,3y)

Using this rule we get

P(3,-6)\rightarrow P'(3(3),3(-6))=P'(9,-18)

Q(6,-9)\rightarrow Q'(3(6),3(-9))=Q'(18,-27)

R(-15,3)\rightarrow R'(3(-15),3(3))=R'(-45,9)

The vertices of image are P'(9,-18), Q'(18,-27) and R'(-45,9).

Therefore, the correct option is C.

6 0
2 years ago
Which equation is equivalent to –k + 0.03 + 1.01k = –2.45 – 1.81k?
ElenaW [278]
K(-1+1.01)+0.03=-2.45-1.81k
0.01k+1.81k=-0.03-2.45
1.82k=-2.42
k=-2.45\1.82=1.3
7 0
2 years ago
x^2+1/2x+1/16=4/9 Factor the perfect-square trinomial on the left side of the equation. (x + )² = 4/9
Nezavi [6.7K]
The missing number is the square-root of the constant term on the left-hand-side, which equals sqrt(1/16)=1/sqrt(16)=1/4.
Check:
(x+1/4)^2=x^2+2*(1/4)x+(1/4)^2=x^2+x/2+1/16.   ok

Answer: x= 1/4
5 0
2 years ago
Read 2 more answers
Mark has a 25 ounce drink. He drinks 5 ounces. What percent of the drink does he have left?
valina [46]

Answer: 80\%

Step-by-step explanation:

This problem can be solved by the <u>Rule of Three</u>, which is a mathematical rule to find out an amount that is with another quantity given in the same relation as other two also known.

In this case, the 25 ounce drink represents the 100 \% . So, if Mark drinks 5 ounces, this means he has 20 ounces left and we have to find the percent this represents:

25 oz ------- 100\%

20 oz -------- ?

?=\frac{(20 oz)(100\%)}{25 oz}

?=80\% This is the percent of the drink Mark has left

4 0
2 years ago
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