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Alja [10]
1 year ago
15

Carlos is analyzing the results of an experiment on two groups of mice in which he compared the difference in their weight gain

after feeding each group a different type of food for one month. The difference in the mean weight gain is 0.6 grams. The standard deviation of the difference in sample means is 0.305.
Mathematics
1 answer:
Arlecino [84]1 year ago
3 0
Given:difference in the mean weight gain is 0.60 gramsstandard deviation of the difference in sample mean is 0.305
68% confidence interval for the population mean difference is a) 0.305
0.60 + 1 * 0.3050.60 + 0.305 = 0.9050.60 - 0.305 = 0.295
95% confidence interval for the population mean difference is c) 0.61
0.60 + 2 * 0.3050.60 + 0.61 = 1.210.60 - 0.61 = -0.01

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a right circular cone has a height of 18 and a base radius of 12. A slice parallel to the base in made completely throught the c
Scrat [10]
<h2>Height of smaller cone is 14.29</h2>

Step-by-step explanation:

\texttt{Volume of cone, V = }\frac{1}{3}\pi r^2h

For the first cone

            Height, h = 18

            Radius, r = 12

Substituting

           \texttt{Volume of cone, V = }\frac{1}{3}\pi r^2h\\\\\texttt{Volume of cone, V = }\frac{1}{3}\times \pi \times 12^2\times 18=2714.34

Volume of new cone formed is half of the older cone.

Volume of new cone = 0.5 x 2714.34 = 1357.17

For the cone as the height reduces to 18 radius reduces to zero.

               tan\theta =\frac{12}{18}\\\\\theta =33.7^0

  \texttt{Volume of new cone = }\frac{1}{3}\pi r_1^2h_1\\\\tan\theta =\frac{r_1}{h_1}\Rightarrow r_1=h_1tan\theta\Rightarrow r_1=h_1tan33.7=0.667h_1\\\\\texttt{Volume of new cone = }\frac{1}{3}\pi \times (0.667h_1)^2h_1=0.467h_1^3

We have

              0.467h₁³ = 1357.17

                       h₁ = 14.29

Height of smaller cone = 14.29

8 0
1 year ago
Read the foxtrot comic strip. write an explanation, including graphs or diagrams, confirming that running "10 yards out, then 10
MAXImum [283]
You want to drwa a diagram

ok, so 10√2 yards at a 45 degree angle

alrighty

let's use a graphing plane
our starting point is at (0,0), the origin
if we go 10 right and 10 up, we end up at (10,10)
now, if we were to draw a line from our starting point (the origin) to the ending point (10,10), we get a line (duh)
if we measure the angle between the line and the x axis, we get 45 degrees
if we find the distance from (0,0) to (10,10) using the distaance formula, we get 10√2  is the distance from (0,0) to (10,10)

so going 10 out and 10 right is same as 10√2 at 45 degree angle


or you could draw a triangle (see diagram)
legs are 10 and 10, connect them to get a hypotnuse
since the legs are equal lengths, the angles are 45-45-90, we have a 45-45-90 triangle
we can either use the special properies of a 45-45-90 triangle (side lenghs are x:x:x√2) or use pythagorean

so remember if te legs are a,b,,c then a²+b²=c²
a=b=10
10²+10²=c²
100+100=c²
200=c²
sqrt both sides
10√2=c

the lenght is 10√2 at a 45 degree angle

4 0
1 year ago
The standard dose of an antibiotic is 4 cc (cubic centimeters) for every 25 pounds of body weight. At this rate, what is the sta
4vir4ik [10]
For this case we can make the following rule of three:
 4 cc ----------------> 25
 x --------------------> 140
 Clearing the value of x we have:
 x = (140/25) * (4)
 x = 22.4 cc
 Answer:
 the standard dose for a 140 pound woman is:
 x = 22.4 cc
6 0
2 years ago
Adriano runs a website that helps writers write better stories. Every month, Adriano receives a subscription fee of \$5$5dollar
jenyasd209 [6]

Answer:

$1002516150

Step-by-step explanation:

200200200 + 404040 -  101010 = 200503230

200503230 x 5 = 1002516150

8 0
1 year ago
Random samples of size 49 are taken from a population that has 200 elements, a mean of 180, and a variance of 196. the distribut
OleMash [197]

Answer:

The mean is 180.

The standard error is 0.286.

Step-by-step explanation:

This question can be solved using the central limit theorem.

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

In this problem, we have that:

The mean of the distribution of the sample means is the same as the mean of the population. This means that the mean is 180.

The standard deviation of the population is the square root of the population variance. So \sigma = \sqrt{196} = 14.

The standard deviation of the sampling distribution of the sample mean is s = \frac{\sigma}{\sqrt{n}} = \frac{14}{\sqrt{49}} = 2.

The standard error of the sampling distribution of the sample mean is SE = \frac{s}{\sqrt{n}} = \frac{2}{7} = 0.286

5 0
1 year ago
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