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Diano4ka-milaya [45]
2 years ago
9

What is 2000(2000^2000)?

Mathematics
1 answer:
Harrizon [31]2 years ago
7 0

Answer:

A. 2000²⁰⁰¹

Step-by-step explanation:

2000(2000²⁰⁰⁰) = 2000²⁰⁰⁰+1 = 2000²⁰⁰¹

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Tessa had $90 in her checking account. She paid her cable/internet bill for $60. She deposited $50 from her part-time job before
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90-60+50-65=15


$15 in her account

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2 years ago
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A bag of marbles can be divided evenly among 2,3 or 4 friends. A) How many marbles might be in the bag? B) What is the least num
agasfer [191]

Answer:

a)12 b)12 c)36

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b) the least common multiple. it is 4*3=...

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then just divide by 2,3,4 to get answer

6 0
2 years ago
Find the quotient. (5x4 – 3x2 4) ÷ (x 1)
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Keywords:

<em>Divide, polynomial, quotient, divisor, dividend, rest </em>

For this case, we must find the quotient by dividing the polynomial (5x ^ 4-3x ^ 2 + 4)\ by\ (x + 1). We must build a quotient that, when multiplied by the divisor, eliminates the terms of the dividend until it reaches the rest, as shown in the attached figure. At the end of the division, to verify we must bear in mind that:

Dividend = Quotient * Divider + Remainder

Answer:

See attached image

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2 years ago
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A gardener uses a tray of 6 conical pots to plant seeds. Each conical pot has a radius of 3 centimeters and a depth of 8 centime
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I think 452cm^3
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2 years ago
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Two tangents drawn to a circle from a point outside it, are equal in length.prove it.<br>​
stiks02 [169]
Given: A circle with centre O; PA and PB are two tangents to the circle drawn from an external point P.
To prove: PA = PB
Construction: Join OA, OB, and OP.
It is known that a tangent at any point of a circle is perpendicular to the radius through the point of contact.
OA⊥PA
OB⊥PB
In △OPA and △OPB
∠OPA=∠OPB (Using (1))
OA=OB (Radii of the same circle)
OP=OP (Common side)
Therefor △OPA≅△OPB (RHS congruency criterion)
PA=PB
(Corresponding parts of congruent triangles are equal)
Thus, it is proved that the lengths of the two tangents drawn from an external point to a circle are equal.
The length of tangents drawn from any external point are equal.
So statement is correct

7 0
2 years ago
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