Given expression :
.
We need to apply power property of logs to rewrite it.
According to log rule of exponents:

If we compare given expression with the rule the exponent part is f, base is 6.
Therefore, we need to bring exponent f in front of log.
Therefore,
.
<h3>And correct option is second option

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For this case, the first thing we must do is define variables.
We have then:
t: the time in minutes
k: the number of kilometers
The relationship between both variables is direct.
Therefore, the function is:

Where, "c" is a constant of proportionality.
To determine "c" we use the following data:
After running for 18 minutes, she completes 2 kilometers.
Substituting values:

Clearing c we have:


Then, the equation is given by:

Answer:
An equation that can be used to represent k, the number of kilometers Julissa runs in t minutes is:

For this, we need to find the lowest common multiple of 12 and 15....
common multiples of 12 : 12,24,36,48,60
common multiples of 15 : 15,30,45,60
LCM = 60
the caller that will be the first to win both is the 60th caller
Answer: a.) 40320
b.) 336
Step-by-step explanation:
since we have 8 possible positions, with 8 different candidates, then there are 8 possible ways of arranging the first position, 7 possible ways of arranging the Second position, 6 ways of arranging the 3rd position, 5 possible ways od arranging the 4th position, 4 possible ways of arranging the 5th position, 3 possible ways of arranging the 6th position, 2 possible ways of arranging the 7th position and just one way of arranging the 8th position since we have only one person left.
Hence, the Number of possible sample space for different 8 positions is by multiplying all the number of ways we have in our sample space which becomes:
8*7*6*5*4*3*2*1 = 40320.
b.) By the sample space we have, since we've been asked ti arrange for only the firat 3 positions, then we multiply just for the first 3ways of choosing the positions, this becomes:
8*7*6 = 336
Answer:
The given coordinates of the vertices of rectangle ABCD are A(−2,2),B(4,2),C(4,−2).
We are to plot D on the graph.
Since ABCD is a rectangle, the abscissa of D will be that of A and the ordinate of D will be that of C.
Step-by-step explanation: