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coldgirl [10]
2 years ago
8

A rancher’s herd of 250 sheep grazes over a 40-acre pasture. He would like to find out how many sheep are grazing on each acre o

f the pasture at any given time, so he has some images of the pasture taken by the state department of agriculture’s aerial photography division. Here are three samples of the images. Sample 1 |4 Sample 2|1 Sample 3|9.
How do the sample statistics compare to the population mean and standard deviation?
Mathematics
2 answers:
Juli2301 [7.4K]2 years ago
6 0
There will be around 8 sheep grazing on each acre
Basile [38]2 years ago
3 0
8.2 sheep grazong on each acre
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A class in advanced physics is composed of 10 juniors, 30 seniors, and 10 graduate students. the final grades show that 3 of the
const2013 [10]

Solution: We are given:

Total students = 10 + 30 + 10 =50

Number of students who received A grade = 3 + 10 + 5 = 18

Number of senior student's who received A grade is = 10

Let A be the event that the student is senior and B be the event that he or she earned an A. Then,

P(A \cap B)=\frac{10}{50}

P(B) = \frac{18}{50}

Now the probability a student chosen at random from this class and is found to have earned an A, the probability that he or she is a senior is:

P(A|B) = \frac{P(A \cap B}{P(B)}

                 =\frac{\frac{10}{50} }{\frac{18}{50} }

                 =\frac{10}{18}=\frac{5}{9} =0.556


5 0
2 years ago
I need to u substitution method to solve -5x-8y=17 , 2x-7y=-17
harina [27]

Answer:

Alright well solve for the variable in one of the equation's. then substitute the result of the other equation

Point form: - 175/51, 1/51

Equation form:

x = - 175/51          y = 1/51 Hope this help's :)


Step-by-step explanation:


8 0
2 years ago
The mean percent of childhood asthma prevalence in 43 cities is 2.32​%. A random sample of 32 of these cities is selected. What
lidiya [134]

Answer:

P(\bar X>2.8)

We can use the z score formula given by:

z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z=\frac{2.8 -2.32}{\frac{1.24}{\sqrt{32}}}=2.190

And using the normal standard distribution and the complement rule we got:

P(z>2.190 )= 1-P(z

Step-by-step explanation:

For this case w eknow the following parameters:

\mu = 2.32 represent the mean

\sigma =1.24 represent the deviation

n= 32 represent the sample sze selected

We want to find the following probability:

P(\bar X>2.8)

We can use the z score formula given by:

z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z=\frac{2.8 -2.32}{\frac{1.24}{\sqrt{32}}}=2.190

And using the normal standard distribution and the complement rule we got:

P(z>2.190 )= 1-P(z

8 0
1 year ago
Read 2 more answers
Charlotte is redecorating the master bedroom in her house. She has purchased a new bedroom set and also plans to paint the room
nasty-shy [4]
Dimensions of the room------------------- >16*13
1 in---------------- >0.0833333 foot
3 in----------------- >x
x=3*.0833333=0.25 ft
Let
<span>C-------------- > dimensions of the piece of carpet that Charlotte must purchase
C-------------- > (16+2*0.25)*(13+2*0.25)---------- > (16.50)*(13.50)=222.75 ft</span>²
<span>
The answer a the question 1) is 16.50 feet X 13.50 feet</span>

The answer a the question 2) is 222.75 ft²

<span>3. How many hours should it take for the four-person crew to lay the flooring in Charlotte's bedroom?

if </span><span>two-person carpet crew can lay 50 square feet of carpet---------- > 1 hour</span><span>
four person </span>carpet crew can lay 100 square feet of carpet---------- > 1 hour

therefore

if  100 ft² carpet----------------------- > 1 hour
 222.75 ft² carpet--------------------- > x
x=222.75/100=2.2275 hours=2.23 hours

The answer is 2.23 hours

6 0
2 years ago
Find the missing side.
Alona [7]

Answer:

9

Step-by-step explanation:

3 0
2 years ago
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