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motikmotik
2 years ago
15

Two brothers build a pyramid-shaped fort. If the fort is 8 feet wide at its base, what expression could be used to calculate the

height of the fort?
Mathematics
2 answers:
Vlada [557]2 years ago
8 0

Answer:

h=4tan\alpha

Step-by-step explanation:

We know that the base is 8 feet wide. The height of the pyramid is at the middle of this width, which forms a right triangle, with the angles formed by one side of the pyramid and the base.

Now, to find the expression of the height, we can use these given information and the trigonometric reasons. Specifically, we would use the tangent from the trigonometric reasons, because the height is the opposite leg to the angle, and the adjacent leg would be 4. So, the expression would be:

tan\alpha=\frac{opposite}{adjacent}\\ tan\alpha=\frac{h}{4}\\ h=4tan\alpha

Therefore, the expression is h=4tan\alpha

melisa1 [442]2 years ago
5 0
Answer: An expression for the height is: H = (3/64)V

To start with, we will assume that it is a square pyramid, meaning all the sides of the base are 8 feet wide.

Now, we need the formula for the volume of a square pyramid.

V = BH/3

We know the area of the base, it is 8 x 8 = 64, so we can input that.

V = 64H/3   We can multiply by 3/64 to find an expression for the height of the fort.

(3/64)V = H
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There are 11 portable mini suites (a.k.a. cages) in a row at the Paws and Claws Holiday Pet Resort. They are neatly labeled with
BigorU [14]

Step-by-step explanation:

a) 7!

If there are no restrictions, answer is 7! as it is the permutation of all animals.

b) 4! x 3!

As cats are 6 and Dogs are 5, thus 1st and last must be cats in order to have alternate arrangements. Therefore the only choices are the order of the cats among  themselves and the order of the dogs among themselves. There are 4! permutations of the cats and 3! permutations of the dogs, so there are a total of 4! x 3! possible arrangements of the suites.

c) 3! x 5!

There are 3! possible arrangements of  the dogs among themselves. Now, if we consider the dogs as  one ”object” together, then we can think of arranging the 4 cats  together with this 1 additional object. There are 5! such arrangements possible, so there are a total of 3! · 5! possible arrangements of the suites.

d) 2 x 4! x 3!

As required that all the cats must be together and all the dogs must be together, either the cats are all  before the dogs or the dogs are all before the cats. There are two possible arrangements thus two times of both possibilities is the answer i.e.  2 x 4! x 3!

3 0
2 years ago
Lisa is 10 centimeters taller than her friend Ian. Ian is 14 centimeters taller than Jim. Every month, their heights increase by
bekas [8.4K]
Let Lisa's height be x, Ian's be y and Jim's be z
x = 10 + y . . . (1)
y = 14 + z . . . (2)
y + 14 + z + 14 = 170 + x + 14
y + z - x = 170 + 14 - 28 = 156 . . . (3)
From (2), z = y - 14 . . . (4)
Putting (1) and (4) into (3) gives,
y + y - 14 - 10 - y = 156
y = 156 + 24 = 180

Therefore, Ian's height is 180 centimeters
5 0
2 years ago
Michael invests USD 20 000 at 9.6% p.a. compounded monthly.
alexandr1967 [171]

Given :

A = 25000

P = 20000

r % = 9.6 % = 0.096

n = 12

To Find :

The time taken say t.

Solution :

We know, compound interest is given by :

A=P(1+\dfrac{r}{n})^{n.t}

Taking log both sides :

A=P(1+\dfrac{r}{n})^{n.t}\\\\log\ \dfrac{A}{P}= n.t\times log( 1+\dfrac{r}{n})\\\\t =\dfrac{1}{n}\times \dfrac{log\ \dfrac{A}{P}}{log(1+\dfrac{r}{n})}\\\\\\t=\dfrac{1}{12}\times \dfrac{log\ \dfrac{25000}{20000}}{log(1+\dfrac{0.096}{12})}\\\\\\t=2.33\ years

Hence, this is the required solution.

5 0
2 years ago
The U.S. Bureau of Labor Statistics reports that 11.3% of U.S. workers belong to unions (BLS website, January 2014). Suppose a s
andrezito [222]

Answer:

a) Null hypothesis:p \leq 0.113  

Alternative hypothesis:p > 0.113  

b) z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing we got:

z=\frac{0.13 -0.113}{\sqrt{\frac{0.113(1-0.113)}{400}}}=1.074  

The p value for this case would be given by:

p_v =P(z>1.074)=0.141  

c) For this case we see that the p value is higher than the significance level of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true proportion workers belonged to unions is significantly higher than 11.3%

Step-by-step explanation:

Information given

n=400 represent the random sample taken

X=52 represent the  workers belonged to unions

\hat p=\frac{52}{400}=0.13 estimated proportion of workers belonged to unions

p_o=0.113 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic

p_v represent the p value

Part a

We want to test if the true proportion of interest is higher than 0.113 so then the system of hypothesis are.:  

Null hypothesis:p \leq 0.113  

Alternative hypothesis:p > 0.113  

Part b

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing we got:

z=\frac{0.13 -0.113}{\sqrt{\frac{0.113(1-0.113)}{400}}}=1.074  

The p value for this case would be given by:

p_v =P(z>1.074)=0.141  

Part c

For this case we see that the p value is higher than the significance level of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true proportion workers belonged to unions is significantly higher than 11.3%

8 0
2 years ago
Mr. Smith had 33 dozen cans. He sold 340 of them at 15$ each. He sold the remaining cans at a discount of 20% each. How much mon
iren2701 [21]

Answer:

Mr. Smith collects $5748 from selling the can.

Step-by-step explanation:

Given total number of cans = 33\times12=396

Selling price of one can = $15.

\therefore \textrm{Selling price of 340 cans} = \textrm {selling price of one can} \times \textrm {number of cans}=15\times340=\$5100

Now remaining number of cans = total number of cans - sold number of cans =396-340=54

For remaining number of cans he gives a discount of 20% each,

∴ Selling price of one can = 15-\frac{15\times20}{100}=15-3=12

∴ Selling price of 54 cans = \textrm{selling price of one can} \times \textrm{number of cans}=12\times54=\$648

So total money he earns =  \$5100+\$648= \$5748.

Thus Mr. Smith earns $5748 by selling the cans.

3 0
2 years ago
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