<u>Part a)</u> if a page is reduced to 80%, what percent enlargement is needed to return it to its original size?
Let
x---------> the percent enlargement
we know that
the original size is the 100%
so
x*80%=100%
x=(100%/80%)
x=1.25--------> 1.25=(125/100)=125%
therefore
<u>the answer Part a) is</u>
the percent enlargement is 125%
<u>Part b)</u> Estimate the number of times in succession that a page must be copied to make the final copy less than 15% of the size of the original
we know that
A photocopy machine can reduce copies to 80% of their original size
so
Copy N 1
0.80*100%=80%
Copy N 2
0.80*80%=64%
Copy N 3
0.80*64%=51.2%
Copy N 4
0.80*51.2%=40.96%
Copy N 5
0.80*40.96%=32.77%
Copy N 6
0.80*32.77%=26.21%
Copy N 7
0.80*26.21%=20.97%
Copy N 8
0.80*20.97%=16.78%
Copy N 9
0.80*16.78%=13.42%-------------> 13.42% < 15%
therefore
<u>the answer Part b) is</u>
the number of times in succession is 9
I believe the answer is B) -3/2 or -1.5.
Please give a heart and rating if this is right!
Answer:
Step-by-step explanation:
Area of trapezium = 1/2 × h (a+b) = 864 cm^2
where h is the height and a and b are the two parallel sides
h = 24 cm
a = 30 cm
b = ?
1/2 × 24 ( 30 + b ) = 864
12 ( 30 + b ) = 864
30 + b = 864/12
30 + b = 72
b = 72 - 30
b = 42
Therefore the lenght of other base = 42 cm
Plz mark it as brainliest !!!!!!!!!!
Answer:
HI B , E
Step-by-step explanation:
I NEED CREADIT
Answer:
23,800 people
Step-by-step explanation:
what is 5 % of 14,000- 700( 0.05 times 14,000)
700 times 14 is 9,800
9800 + 14000 is
