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dezoksy [38]
2 years ago
11

Every sunny day, the Always Philadelphia Bakery bakes 100 cakes and 60 muffins. In any other weather, it bakes 40 cakes and 120

muffins per day. This April, the Always Philadelphia Bakery made the same number of cakes as muffins. How many of this April’s 30 days were sunny?
Mathematics
2 answers:
pantera1 [17]2 years ago
8 0

Answer:


Step-by-step explanation:

For All Sweets Bakery, the daily sales ratio of bread to cakes is 5:2. ... more loaves of bread on Tuesday than its daily sale of 40 loaves, how many cakes were ... twice as much sugar as milk, eight times more milk than baking powder and twice ... and convert the ratios to 15 cookies : 10 cupcakes and 15 cookies : 18 pastries.

DanielleElmas [232]2 years ago
7 0

Answer:

20 days

Step-by-step explanation:

Let x be the # of sunny days.

100x + 40(30-x) = 60x + 120(30-x)

x=20

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1 year ago
A. imagine that you are one of the people who left the luncheon with a contagious disease and interacted with an average of 9 di
shusha [124]

1.       In line with the test each person who came into interaction with the infected person will become infected also. With this information, the calculation would be: 9 people each day for 7days would be equivalent to 9 x 7 which equals 63 people.

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2 years ago
Please answer all of them need this
VikaD [51]

First Question

For a better understanding of the solution provided here please find the first attached file which has the diagram of the the isosceles trapezoid.

We dropped perpendiculars from C and D to intersect AB at Q and P respectively.

As can be seen in \Delta BCQ, we can easily find the values of CQ and BQ.

Since, Sin(75^0)=\frac{CQ}{8}

\therefore CQ=8\times Sin(75^0)\approx 7.73 ft

In a similar manner we can find BQ as:

Cos(75^0)=\frac{BQ}{8}

BQ\approx2.07 ft

All these values can be found in the diagram attached.

Thus, because of the inherent symmetry of the isosceles trapezoid, PQ can be found as:

PQ=22-(AP+QB)=22-(2.07+2.07)=17.86

Let us now consider\Delta AQC

We can apply the Pythagorean Theorem here to find the length of the diagonal AC which is the hypotenuse of \Delta AQC.

AC=\sqrt{(AQ)^2+(QC)^2}=\sqrt{(AP+PQ)^2+(QC)^2}=\sqrt{(2.07+17.86)^2+(7.73)^2}\approx21.38 feet.

Thus, out of the given options, Option B is the closest and hence is the answer.

Second Question

For this question we can directly apply the formula for the area of a triangle using sines which is as:

Area=\frac{1}{2}(First Side)(Second Side)(Sine of the angle between the two sides)

Thus, from the given data,

Area=\frac{1}{2}\times 218.5\times 224.5\times sin(58.2^0)\approx20845 m^2

Therefore, Option D is the correct option.

Third Question

For this question we will apply the Sine Rule to the \Delta ABC given to us.

Thus, from the triangle we will have:

\frac{AB}{Sin(\angle C)}=\frac{BC}{Sin(\angle A)}

\frac{c}{Sin(\angle C)}=\frac{a}{Sin(\angle A)}

\frac{17}{Sin(25^0)}=\frac{a}{Sin(45^0)}

This gives a to be:

a\approx28.44

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Fourth Question

Please find the second attachment for a better understanding of the solution provided her.

As can be clearly seen from the attached diagram, we can apply the Cosine Rule here to find the return distance of the plane which is CA.

AC=\sqrt{(AB)^2+(BC)^2-2(AB)(BC)\times Cos(\angle B)}

\therefore AC=\sqrt{(172.20)^2+(111.64)^2-2(172.20)(111.64)\times Cos(177.29^0)}\approx283.8 miles.

Thus, Option D is the answer.





8 0
2 years ago
Read 2 more answers
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gladu [14]

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 6.25\leq6.3

Where \leq indicates that the value 6.25 is included and indicates that the value 6.35 is not included (Because if x had been exactly 6.35, Cynthia would round up to 6.4).

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Sati [7]
It's Dublin - San Juan


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