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adell [148]
2 years ago
5

You have volunteered to be tested for psychic powers. There are 8 cards, 2 of which have a square on them, 2 of which have a tri

angle on them, 2 of which have a circle on them, and 2 of which have a star on them. The tester shuffles the cards, then looks at each card in turn, without letting you see it, and tries to send the picture psychically to you. You guess a picture randomly each time. Let X be the number of times you guess correctly. What is the probability that you will get 3 pictures right?
Mathematics
1 answer:
klasskru [66]2 years ago
5 0

Answer:

The probability that you will get 3 pictures right is 0,015625

Step-by-step explanation:

To get the probability, equally likely, of guessing the picture we use the following formula

P=# of possibilities that meet the condition / #of equally likely possibilities.

# of possibilities that meet the condition= 2

#of equally likely possibilities= 8

So every time you guees you have 2 possibilities from 8 ,  that give us a probability of 2/8 or 1/4

We suppose once you guess 1 card ,  the tester put back the card with the others.  

Now,  we must guess 3 pictures,  that will be the multiplication of each probability.

P= 1/4 *1/4*1/4

P= 0,015625

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Another set of triangles has a height of 2.9 and a base of 3.8.
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1 year ago
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Answer:

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Step-by-step explanation:

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Answer:

Check the explanation

Step-by-step explanation:

One way ANOVA

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Alternative hypothesis: There is a significance difference in the averages of the scores for the quizzes, exams and final only.

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In the attached image below, we are given that the p-value = 0.0221 and level of significance or alpha value = 0.05, that is p-value is less than the given level of significance. So, we reject the null hypothesis that there is no significant difference in the averages of the scores for the quizzes, exams and final only. This means we conclude that there is a significance difference in the averages of the scores for the quizzes, exams and final only.

3 0
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4 markers cost $7.04. Which equation would help determine the cost of 7 markers??
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7 0
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