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2 years ago

What are the solutions of the quadratic equation 40-x^2=0

2 answers:

3 0

Use the quadratic formula to find the solutions:−b±√b2−4(ac)2a-b±b2-4(ac)2a Substitute the values:
a=−1a=-1, b=0b=0, and c=40c=40 into the quadratic formula and solve for x 0±√02−4⋅(−1⋅40)2⋅−10±02-4⋅(-1⋅40)2⋅-1 Simplify:
x=±2√10x=±210 The result can be shown in both exact and approximate form: x=±2√10x=±210x≈6.324555,−6.324555
I hope this helps. :)

MAVERICK [17]2 years ago

3 0

Answer:

The answer is approximately ±6.32

Step-by-step explanation:

Given the quadratic equation 40-x² = 0, to get the solution to the quadratic equation, we must find all the values of x that satisfies the equation.

From the equation 40-x²= 0

Step1: Take -x² to the other side of the equation to have;

40= 0+x²

40= x²

Step 2: Take the square root of both sides to have;

√40 = √x²

x = ±√40

x = ±6.32

The values of x are approximately 6.32 and -6.32

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