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VladimirAG [237]

2 years ago

10

Jack and Walter work in a store's gift-wrapping department. Jack can wrap 28 boxes in 2 hours, while Walter takes 3 hours to wra

p 36 boxes of the same size. One day they work together for t hours to gift wrap 65 boxes. Which equation models this situation?

1 answer:

iVinArrow [24]2 years ago

4 0

J = 14h
w = 12h
h = jw65

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I talk to an average of 8 customers per hour during an 8 hour shift and need to increase the amount of customers i help by 20%,

lbvjy [14]

Answer:

The number of customer needed to achieve is 34

Step-by-step explanation:

Given as :

The number of customer per hour = 8

The time taken = 8 hours

The rate of increase = 20 %

Let The increase in number of customer after 20 % increment = x

So , The number of customer after n hours = initial number × $(1+\dfrac{\textrm rate}{100})^{n}$

or, The number of customer after 8 hours = 8 × $(1+\dfrac{\textrm 20}{100})^{8}$

or, The number of customer after 8 hours = 8 × 4.2998

∴The number of customer after 8 hours = 34.39 ≈ 34

Hence The number of customer needed to achieve is 34 answer

8 0

2 years ago

A rectangular portrait measures 50cm by 70cm. It is surrounded by a rectangular frame of uniform width. If the area of the frame

snow_tiger [21]

Let us assume uniform width = x cm wide.

Length of rectangular portrait = 50cm and width of rectangular portrait = 70cm.

Therefore, length of rectangle made by frame = 50 + x+x = (2x+50) cm.

And width of rectangle made by frame = 70+x+x = (2x+70) cm.

We know, the area of rectangular portrait = 50 × 70 = 3500 cm^2.

Total area of the rectangle made by frame would be = (2x+50) * (2x+70)

We know,

Actual area of frame = Area of rectangle made by frame - area of rectangular portrait.

We also given "the area of the frame is the same as the area of the portrait."

We can setup an equation now,

3500 = (2x+50) * (2x+70) - 3500.

Subtracting 3500 from both sides, we get

3500-3500 = (2x+50) * (2x+70) - 3500-3500.

0 = (2x+50) * (2x+70) -7000.

FOIL (2x+50) * (2x+70), we get

0 = 2x*2x +2x*70 + 50*2x +50*70 - 7000.

0 = 4x^2 +140x +100x +3500 -7000.

4x^2 +240x -3500 = 0.

Dividing whole equation by 4, we get

x^2 +60x - 875 =0

Applying quadratic formula $=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ , we get

$=\frac{-60\pm \sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}$

$x=\frac{-60+\sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}=5\left(\sqrt{71}-6\right)$

$x=\frac{-60-\sqrt{60^2-4\cdot \:1\left(-875\right)}}{2\cdot \:1}:\quad -5\left(6+\sqrt{71}\right)$

We cant take negative value.

So, $x=5\left(\sqrt{71}-6\right)=12.13$

We could take approximately 12 cm.

7 0

2 years ago

Consumer Reports scored cars on quality and cost. Spearman's rank correlation coefficient was calculated using Statdisk and the

melomori [17]

Answer:

d.There is insufficient evidence to conclude that the quality and price of a car are associated. There were ten cars used in the sample.

Step-by-step explanation:

Hello!

You have two variables X₁: quality score of a car and X₂: the price of a car.

It was analyzed id there is an association between the quality and the price.

The null hypothesis of a Spearman's rank correlation test is:

H₀: There is no association between the quality and the price of cars.

The researcher failed to reject the null hypothesis which means that there is no association between the variables of interest.

The sample size is listed in the output n= 10 consumer reports.

I hope you have a SUPER day!

8 0

2 years ago

Find the average value of the function f(x, y, z) = 5x2z 5y2z over the region enclosed by the paraboloid z = 4 − x2 − y2 and the

S_A_V [24]

The paraboloid meets the x-y plane when x²+y²=9. A circle of radius 3, centre origin.

<span>Use cylindrical coordinates (r,θ,z) so paraboloid becomes z = 9−r² and f = 5r²z. </span>

<span>If F is the mean of f over the region R then F ∫ (R)dV = ∫ (R)fdV </span>

<span>∫ (R)dV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] rdrdθdz </span>

<span>= ∫∫ [θ=0,2π, r=0,3] r(9−r²)drdθ = ∫ [θ=0,2π] { (9/2)3² − (1/4)3⁴} dθ = 81π/2 </span>

<span>∫ (R)fdV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] 5r²z.rdrdθdz </span>

<span>= 5∫∫ [θ=0,2π, r=0,3] ½r³{ (9−r²)² − 0 } drdθ </span>

<span>= (5/2)∫∫ [θ=0,2π, r=0,3] { 81r³ − 18r⁵ + r⁷} drdθ </span>

<span>= (5/2)∫ [θ=0,2π] { (81/4)3⁴− (3)3⁶+ (1/8)3⁸} dθ = 10935π/8 </span>

<span>∴ F = 10935π/8 ÷ 81π/2 = 135/4</span>

3 0

2 years ago

Which is the correct answer?

deff fn [24]

Answer:

The answer is H 3

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers