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Tpy6a [65]
1 year ago
6

The equation of a circle is x2 + y2 + Cx + Dy + E = 0. If the radius of the circle is decreased without changing the coordinates

of the center point, how are the coefficients C, D, and E affected?
Mathematics
2 answers:
tatyana61 [14]1 year ago
6 0

Answer:

There will be no change in C and D but E must increase.

Step-by-step explanation:

We are given a equation of circle as:

x^2+y^2+Cx+Dy+E = 0

it could also be represented in general form of equation of circle as:

(x+\dfrac{C}{2})^2+(y+\dfrac{D}{2})^2=\dfrac{C^2}{4}+\dfrac{D^2}{4}-E

( since we add both the side of the equality by \dfrac{C^2}{4} and  \dfrac{D^2}{4} )

Hence, on comparing the equation with general form of the equation:

(x-g)^2+(y-h)^2=r^2

The center of circle is (g,h) and radius is r.

Here we have the center as:

(\dfrac{-C}{2},\dfrac{-D}{2})

and radius is given aS:

r=\sqrt{\dfrac{C^2}{4}+\dfrac{D^2}{4}-E}\\\\r=\sqrt{\dfrac{C^2+D^2-4E}{4}

r=\dfrac{\sqrt{C^2+D^2-4E}}{2}

As there is no change in the center hence the value of \dfrac{-C}{2} and \dfrac{-D}{2} remains unchanged i.e. the value of C and D remains unchanged.

Now we are given that the radius of the circle is decreased.

that means the change in radius is due to the change in E.

Hence for the quantity r=\dfrac{\sqrt{C^2+D^2-4E}}{2}\\ to decrease E must increase so that the total quantity decreases.

Hence there will be no change in C and D but E must increase in order to decrease the radius of circle.

Tcecarenko [31]1 year ago
3 0

Answer: C and D will be unaffected while E will increase.

Step-by-step explanation:

Given equation of a circle is,

x^2+y^2+Cx+Dy+E=0

But we know that the equation of the circle,

(x-h)^2+(y-k)^2=r^2

Where, (h,k) is the center of circle and r is the radius of circle,

We know that, (a-b)² = a² - 2ab + b²,

\implies x^2-2hx+h^2+y^2-2yk+k^2=r^2

\implies x^2+y^2-2hx-2yk+(h^2+k^2-r^2)=0

By comparing,

C=-2h,

D=-2y,

E=h^2+k^2-r^2

Thus, by the above values, we can say that,

If r decreases C will be unaffected ( because C is free from r)

D will be unaffected ( because D is also free from r)

While, E will be increased.

Hence, C and D will be unaffected while E will increase if radius decreases.

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Answer:

w/2 = 7.5/5

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Step-by-step explanation:

Remaining question below:

Which proportion could Maddy use to model this situation?

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Answer:

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Step-by-step explanation:

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Z has a pvalue of 0.95 between 1.64 and 1.65. So we use Z = 1.645

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The number of units is discrete, this means that the bonus will be paid on at least 4099 units.

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Answer:

a) \bar X \sim N(\mu=30, \frac{2}{\sqrt{16}})

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Step-by-step explanation:

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The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Let X the random variabl length of advertisements produced by Majesty Video Production Inc. We know from the problem that the distribution for the random variable X is given by:

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We take a sample of n=16 . That represent the sample size.

a. What can we say about the shape of the distribution of the sample mean time?

From the central limit theorem we know that the distribution for the sample mean \bar X is also normal and is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

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b. What is the standard error of the mean time?

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c. What percent of the sample means will be greater than 31.25 seconds?

In order to answer this question we can use the z score in order to find the probabilities, the formula given by:

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d. What percent of the sample means will be greater than 28.25 seconds?

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And we want to find this probability:

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e. What percent of the sample means will be greater than 28.25 but less than 31.25 seconds?"

We want this probability:

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We have been given that a company makes wax candles in the shape of a solid sphere. Each candle has a diameter of 15 cm. We are asked to find the number of candles that company can make from 70,650 cubic cm of wax.

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We know that radius is half the diameter, so radius of each candle will be \frac{15}{2}=7.5 cm.

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