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Simora [160]
2 years ago
10

I need to increase the number of customers by 20% daily, I talk to an average of 8 customers per hour during an 8 hour shift so

now ill need to talk to how many customers per day?
Mathematics
2 answers:
vivado [14]2 years ago
7 0

Answer:

The number of customer per day is 10.

Step-by-step explanation:

Given : I need to increase the number of customers by 20% daily, I talk to an average of 8 customers per hour during an 8 hour shift.

To find : How many customers per day?

Solution :

We have an average of 8 customers.

Increase the number of customers by 20% daily.

i.e. increased number will be 20% of 8,

20\%\times 8=0.2\times 8=1.60

i.e. 1.60 customer per hour during an 8 hour shift.

So, 8+1.60=9.60

Approximately the number of customer per day is 10.

MA_775_DIABLO [31]2 years ago
6 0

Before we figure out how many customers you will need to talk per day to reach your goal, let's calculate what is 20% of how many customers you normally talk to a day.


current no. = 8

goal = 8 + 20%

20% = 8 x 0.20

(a percent is really just a fraction with the percent number over 100)

20% = 1.60

goal = 8 + 1.60

goal = 9.60


However, there is no such thing as .60 of a person so we will have to round up. You will need to talk to 10 customers per day.

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Answer:

The ticket price that maximizes revenue is $50.

The maximum monthly revenue is $250,000.

Step-by-step explanation:

We have to write a function that describes the revenue of the airline.

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R(x)=(30+x)(7000-100x)=30\cdot7000-30\cdot100x+7000x-100x^2\\\\R(x)=-100x^2+(7000-3000)x+210000\\\\R(x)=-100x^2+4000x+210000\\\\\\\dfrac{dR}{dx}=100(-2x)+4000=0\\\\\\200x=4000\\\\x=4000/200=20

We know that the increment in price (from the $30 level) that maximizes the revenue is $20, so the price should be:

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The maximum monthly revenue is:

R(x)=(30+x)(7000-100x)\\\\R(20)=(30+20)(7000-100\cdot20)\\\\R(20)=50\cdot5000\\\\R(20)=250000

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