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Simora [160]
2 years ago
10

I need to increase the number of customers by 20% daily, I talk to an average of 8 customers per hour during an 8 hour shift so

now ill need to talk to how many customers per day?
Mathematics
2 answers:
vivado [14]2 years ago
7 0

Answer:

The number of customer per day is 10.

Step-by-step explanation:

Given : I need to increase the number of customers by 20% daily, I talk to an average of 8 customers per hour during an 8 hour shift.

To find : How many customers per day?

Solution :

We have an average of 8 customers.

Increase the number of customers by 20% daily.

i.e. increased number will be 20% of 8,

20\%\times 8=0.2\times 8=1.60

i.e. 1.60 customer per hour during an 8 hour shift.

So, 8+1.60=9.60

Approximately the number of customer per day is 10.

MA_775_DIABLO [31]2 years ago
6 0

Before we figure out how many customers you will need to talk per day to reach your goal, let's calculate what is 20% of how many customers you normally talk to a day.


current no. = 8

goal = 8 + 20%

20% = 8 x 0.20

(a percent is really just a fraction with the percent number over 100)

20% = 1.60

goal = 8 + 1.60

goal = 9.60


However, there is no such thing as .60 of a person so we will have to round up. You will need to talk to 10 customers per day.

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Suppose that 4% of the 2 million high school students who take the SAT each year receive special accommodations because of docum
dangina [55]

Answer:

a. 0.0122

b. 0.294

c. 0.2818

d. 30.671%

e. 2.01 hours

Step-by-step explanation:

Given

Let X represents the number of students that receive special accommodation

P(X) = 4%

P(X) = 0.04

Let S = Sample Size = 30

Let Y be a selected numbers of Sample Size

Y ≈ Bin (30,0.04)

a. The probability that 1 candidate received special accommodation

P(Y = 1) = (30,1)

= (0.04)¹ * (1 - 0.04)^(30 - 1)

= 0.04 * 0.96^29

= 0.012244068467946074580191760542164986632531806368667873050624

P(Y=1) = 0.0122 --- Approximated

b. The probability that at least 1 received a special accommodation is given by:

This means P(Y≥1)

But P(Y=0) + P(Y≥1) = 1

P(Y≥1) = 1 - P(Y=0)

Calculating P(Y=0)

P(Y=0) = (0.04)° * (1 - 0.04)^(30 - 0)

= 1 * 0.96^36

= 0.293857643230705789924602253011959679180763352848028953214976

= 0.294 --- Approximated

c.

The probability that at least 2 received a special accommodation is given by:

P (Y≥2) = 1 -P(Y=0) - P(Y=1)

= 0.294 - 0.0122

= 0.2818

d. The probability that the number among the 15 who received a special accommodation is within 2 standard deviations of the number you would expect to be accommodated?

First, we calculate the standard deviation

SD = √npq

n = 15

p = 0.04

q = 1 - 0.04 = 0.96

SD = √(15 * 0.04 * 0.96)

SD = 0.758946638440411

SD = 0.759

Mean =np = 15 * 0.04 = 0.6

The interval that is two standard deviations away from .6 is [0, 2.55] which means that we want the probability that either 0, 1 , or 2 students among the 20 students received a special accommodation.

P(Y≤2)

P(0) + P(1) + P(2)

=.

P(0) + P(1) = 0.0122 + 0.294

Calculating P(2)

P(2) = (0.04)² * (1 - 0.04)^(30 - 2(

P(2) = 0.00051

So,

P(0) +P(1) + P(2). = 0.0122 + 0.294 + 0.00051

= 0.30671

Thus it 30.671% probable that 0, 1, or 2 students received accommodation.

e.

The expected value from d) is .6

The average time is [.6(4.5) + 19.2(3)]/30 = 2.01 hours

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Given:

It is given that surface area must be less than 150 cm².

Solution:

The Maximum Volume With Total Surface Area Less  than 150 cm² is shown in the table.

From the table, it can be concluded that for r=3.00 cm and h=4.95 cm the surface area will be less than 150 cm²  and the volume will be the maximum.

S=2\pi rh+2\pi r^2\\S=2\pi (3)(7.95)+2\pi3^2\\S=93.3+56.5\\S=149.8 \text{ cm}^2

Calculate the volume.

V=\pi r^2h\\V=\pi(3)^2(4.95)\\V=139.96

Hence, the required dimensions are r=3.00 cm and h=4.95 cm.

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Answer:

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Using the p value calculation.

1. Check the left tailed z table as the test statistic is negative,

2. Then find the probabilitythat z is greater than your test statistic (look up your test statistic on the z-table- the value under 1.2 and 0.05 which is 0.8944

3. Then, find its corresponding probability, and subtract it from 1 to get your p-value- 1-0.8944 = 0.1056.

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