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liq [111]
1 year ago
15

If PQ=RS, which of the following must be true?

Mathematics
1 answer:
maw [93]1 year ago
4 0

<u>Answer:</u>

If PQ=RS then PQ and RS have the same length. Hence option D is correct

<u>Solution:</u>

Given that, pq = rs  

And, we have to find which of the given options are true.

<u><em>a) pq and rs form a straight angle </em></u>

We can’t decide the angle in between pq and rs just by the statement pq = rs.

So this statement is false.

<u><em>b) pq and rs form a zero angle. </em></u>

We can’t decide the angle in between pq and rs just by the statement pq = rs.

So this statement is false.

<u><em>c) pq and rs are same segment. </em></u>

If two things equal then there is no condition that both represents a single item.

So this statement is false.

<u><em>d) pq and rs have the same length </em></u>

As given that pq = rs, we can say that they will have the same length  

Hence, option d is true.

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A manager wants to build 3-sigma x-bar control limits for a process. The target value for the mean of the process is 10 units, a
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Answer: Third option is correct.

Step-by-step explanation:

Since we have given that

Mean = 10

Sample size = 9

Standard deviation = 6

We need to find the upper and lower control limits.

so, Lower limit would be

\bar{x}-3\dfrac{\sigma}{\sqrt{n}}\\\\=10-3\times \dfrac{6}{\sqrt{9}}\\\\=10-6\\\\=4

Upper limit would be

\bar{x}+3\dfrac{\sigma}{\sqrt{n}}\\\\=10+3\times \dfrac{6}{\sqrt{9}}\\\\=10+6\\\\=16

Hence, Third option is correct.

3 0
2 years ago
ΔABC is an equilateral triangle. m∠A = (3x - 12)°. Solve for x. A) 14 B) 19 C) 20 D) 24
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Answer:

c is the answer

Step-by-step explanation:

hope it is correct tho

8 0
1 year ago
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Hannah took $50.00 to go shopping and she bought 2 shirts for $17.00 each how change did she have left
Vlad1618 [11]

Answer: Hannah had $16.00 left.

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4 0
1 year ago
PI-3.
Fudgin [204]

Answer:

A. $301

B. $721

Step-by-step explanation:

Let $x be the amount of money they raised.

Rowena tried to put the $1 bills into two equal piles and found one left over at the end, then

x=2q_1+1

Polly tried to put the $1 bills into three equal piles and found one left over at the end, then

x=3q_2+1

Frustrated, they tried 4, 5, and 6 equal piles and each time had $1 left over, then

x=4q_3+1\\ \\x=5q_4+1\\ \\x=6q_5+1

Finally Rowena put all the bills evenly into 7 equal piles, and none were left over, then

x=7q_6

This means x-1 is divisible by 2, 3, 4, 5 and 6 without remainder, so

x-1=2\cdot 3\cdot 2\cdot 5n=60n

Hence,

x=60n+1, \ n\in N

The smallest amount of money they could have raised is $301, because

x=60\cdot 5+1=301 is divisible by 7.

Now, the number x=60n+1 should be divisible by 7 and must be greater than 500.

So,

60n+1>500\\ \\60n>499\\ \\n>8

When n = 9,

x=60\cdot 9+1=541 is not divisible by 7.

When n = 10,

x=60\cdot 10+1=601 is not divisible by 7.

When n = 11,

x=60\cdot 11+1=661 is not divisible by 7.

When n = 12,

x=60\cdot 12+1=721 is divisible by 7.

B. The least amount of money they could have raised is $721

7 0
2 years ago
Read 2 more answers
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