(a) The probability that there is no open route from A to B is (0.2)^3 = 0.008.
Therefore the probability that at least one route is open from A to B is given by: 1 - 0.008 = 0.992.
The probability that there is no open route from B to C is (0.2)^2 = 0.04.
Therefore the probability that at least one route is open from B to C is given by:
1 - 0.04 = 0.96.
The probability that at least one route is open from A to C is:

(b)
α The probability that at least one route is open from A to B would become 0.9984. The probability in (a) will become:

β The probability that at least one route is open from B to C would become 0.992. The probability in (a) will become:

Gamma: The probability that a highway between A and C will not be blocked in rush hour is 0.8. We need to find the probability that there is at least one route open from A to C using either a route A to B to C, or the route A to C direct. This is found by using the formula:


Therefore building a highway direct from A to C gives the highest probability that there is at least one route open from A to C.
Step-by-step explanation:
f(x)=x²+10x-24
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Answer:

Step-by-step explanation:
<u><em>The complete question is</em></u>
Given the quadrilateral is a rectangle, if LO = 15x+19 and QN = 10x+2 find PN
see the attached figure to better understand the problem
we know that
The diagonals of a rectangle are congruent and bisect each other
so

substitute the given values

solve for x

Find the length of PN
Remember that
----> diagonals of rectangle are congruent

substitute the value of x

therefore

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