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saveliy_v [14]
2 years ago
13

Which algebraic expression shows the average melting points of helium, hydrogen, and neon if h represents the melting point of h

elium, j represents the melting point of hydrogen, and k represents the melting point of neon?
A. h + j + k
B. hjk
c. h+j+k over 3
d. hjk over 3
Mathematics
2 answers:
Ainat [17]2 years ago
8 0

Answer:

c. h+j+k over 3

Step-by-step explanation:

We know that,

\text{Average}=\frac{\text{Sum of observations}}{\text{Total number of observation}}

Here, h, j and k represents the melting point of helium, hydrogen and Neon respectively,

Since, the sum of melting points = h + j + k,

Also, the total number of gases = 3,

Thus,

\text{Average melting points}=\frac{h+j+k}{3}

Or (h+j+k) over 3

⇒ Option c is correct.

LenKa [72]2 years ago
4 0
Average = mean = sum of the values / number of data

Values = h, j, and k

Number of data = 3

Sum of the values = h + j + k

Mean = [h + j + k] / 3

=> Answer: option c. [h+j+k] over 3
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Conditional probability is a measure of the probability of an event given that another event has occurred. If the event of interest is A and the event B is known or assumed to have occurred, "the conditional probability of A given B", or "the probability of A under the condition B", is usually written as P(A|B), or sometimes P_B(A).

The conditional probability of event A happening, given that event B has happened, written as P(A|B) is given by
P(A|B)= \frac{P(A \cap B)}{P(B)}

In the question, we were told that there are three randomly selected coins which can be a nickel, a dime or a quarter.

The probability of selecting one coin is \frac{1}{3}

Part A:
To find <span>the probability that all three coins are quarters if the first two envelopes Jeanne opens each contain a quarter, let the event that all three coins are quarters be A and the event that the first two envelopes Jeanne opens each contain a quarter be B.

P(A) means that the first envelope contains a quarter AND the second envelope contains a quarter AND the third envelope contains a quarter.

Thus P(A)= \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} = \frac{1}{27}

</span><span>P(B) means that the first envelope contains a quarter AND the second envelope contains a quarter

</span><span>Thus P(B)= \frac{1}{3} \times \frac{1}{3} = \frac{1}{9}

Therefore, P(A|B)=\left( \frac{ \frac{1}{27} }{ \frac{1}{9} } \right)= \frac{1}{3}


Part B:
</span>To find the probability that all three coins are different if the first envelope Jeanne opens contains a dime<span>, let the event that all three coins are different be C and the event that the first envelope Jeanne opens contains a dime be D.
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P(C)= \frac{3}{3} \times \frac{2}{3} \times \frac{1}{3} = \frac{6}{27} = \frac{2}{9}

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Answer:

r = 0.9825; good correlation.

Step-by-step explanation:

One formula for the correlation coefficient is  

r = \dfrac{n\sum{xy} - \sum{x} \sum{y}}{\sqrt{n\left [\sum{x}^{2}-\left (\sum{x}\right )^{2}\right]\left [\sum{y}^{2}-\left (\sum{y}\right )^{2}\right]}}

The calculation is not difficult, but it is tedious.

1. Calculate the intermediate numbers

We can display them in a table.

      <u> </u><u>x</u>    <u>  y </u>   <u>  xy </u>  <u> x² </u>    <u>   y²   </u>

      -3   -40    120     9     1600

       1      12      12      1        144

       5    72   360   25      5184

     <u>  7</u>   <u>137</u>  <u> 959</u>   <u>49</u>    <u>18769 </u>

Σ = 10   181  1451   84   25697

2. Calculate the correlation coefficient

r = \dfrac{n\sum{xy} - \sum{x} \sum{y}}{\sqrt{\left [n\sum{x}^{2}-\left (\sum{x}\right )^{2}\right]\left [n\sum{y}^{2}-\left (\sum{y}\right )^{2}\right]}}\\\\= \dfrac{4\times 1451 - 10\times 181}{\sqrt{[4\times 84 - 10^{2}][4\times25697 - 181^{2}]}}\\\\= \dfrac{5804 - 1810}{\sqrt{[336 - 100][102788 - 32761]}}\\\\= \dfrac{3994}{\sqrt{236\times70027}}\\\\= \dfrac{3994}{\sqrt{16526372}}\\\\= \dfrac{3994}{4065}\\\\= \mathbf{0.9825}

The closer the value of r is to +1 or -1, the better the correlation is. The values of x and y are highly correlated.

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J can find the height of the fifth member on this way
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S1=153
S2=150
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S4=152
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Point G is on segment FH such that it partitions segment FH into a ratio of 2:3.Point F is located at (5, 7) and point H is loca
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Answer:

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Step-by-step explanation:

The ratio is applied in the x-distance and the y-distance. The ratio is 2:3 so you have to divide the distances by 5 and 2/5 correspond to FG and 3/5 to GH

x-distance:

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11/5 = 2.2

y-distance:

y2 - y1 = 13 - 7 = 6

6/5 = 1.2

Point G = Point F + (2.2*2, 1.2*2)

Point G = (5, 7) + (4.4, 2.4)

= (9.4, 9.4)

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