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Lady_Fox [76]
2 years ago
11

A bicycle is traveling at 20 feet per minute. What is the bicycle's speed expressed in inches per second?

Mathematics
1 answer:
Vikentia [17]2 years ago
7 0

Answer:

4 inches per second

Step-by-step explanation:

Speed = distance/time

Given

Distance = 20 feet

12 inches = 1 foot

X inches = 20 feet

X = 20 x 12 = 240 inches

Time = 1 minute = 60 secs

Therefore

Speed = 240/60

= 4 inches per second

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Answer:

Geometric

Step-by-step explanation:

A geometric setting does not have a set number of trials, and the variable in question is the number of trials it takes to get the first success.

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4 0
1 year ago
Read 2 more answers
1. & 2. In the diagram below, points A, B, and C are collinear. Answer each of the following questions. The figure shown bel
KiRa [710]

Answer:

a). AB = 8 in

b). AB = 9.75 in

c). AC = 6.5 in

d). BC = 1.5 in

Step-by-step explanation:

a). Since, AB = AC + CB

   Length of AC = 5 in. and CB = 3 in.

   Therefore, AB = 5 + 3 = 8 in.

b). Given : AC = 6.25 in and CB = 3.5 in

   Therefore, AB = AC + CB = 6.25 + 3.5

   AB = 9.75 in.

c). Given: AB = 10.2 in. and BC = 3.7 in.

    AB = AC + BC

    AC = AB - BC

    AC = 10.2 - 3.7

    AC = 6.5 in

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4 0
1 year ago
Divide 169 mi in the ratio 5 : 8.
krek1111 [17]
The answer is 169/5:8 = 5. It helps me alot it could help you to.
3 0
1 year ago
Exams are approaching and Helen is allocating time to studying for exams. She feels that with the appropriate amount of studying
svp [43]

Answer: 0.05

Step-by-step explanation:

Let M = Event of getting an A in Marketing class.

S = Event of getting an A in Spanish class,

i.e. P(M) = 0.80 , P(S) = 0.60 and P(M∩S)=0.45

Required probability = P(neither M nor S)

= P(M'∩S')

= P(M∪S)'                                 [∵P(A'∩B')=P(A∪B)']

=1- P(M∪S)                               [∵P(A')=1-P(A)]

= 1- (P(M)+P(S)- P(M∩S))   [∵P(A∪B)=P(A)+P(B)-P(A∩B)]

= 1- (0.80+0.60-0.45)

= 1- 0.95

= 0.05

hence, the probability that Helen does not get an A in either class= 0.05

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2 years ago
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I'm thinking I no this one hold up
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