Ask question

Ask question

All categories

1 year ago

13

Here is another riddle: The sum of two numbers is less than 2. If we subtract the second number from the first, the difference i

s greater than 1. What are the two numbers? The riddle can be represented by a system of inequalities. Write an inequality for each statement.

1 answer:

aivan3 [116]1 year ago

4 0

Answer:

Let x, y be the two numbers under consideration. Then, x+y<2 and x-y>1.

You might be interested in

Which of the following is the expansion of (3c + d2)6?

vovangra [49]

Answer: Option A) $729c^6 + 1,458c^5d^2 + 1,215c^4d^4 + 540c^3d^6 + 135c^2d^8 + 18cd^{10} + d^{12}$ is the correct expansion.

Explanation:

on applying binomial theorem, $(a+b)^n=\sum_{r=0}^{n} \frac{n!}{r!(n-r)!} a^{n-r} b^r$

Here a=3c, $b=d^2$ and n=6,

Thus, $(3c+d^2)^6=\sum_{r=0}^{6} \frac{6!}{r!(6-r)!} (3c)^{n-r} (d^2)^r$

⇒ $(3c+d^2)^6= \frac{6!}{(6-0)!0!} (3c)^{6-0}.(d^2)^0+\frac{6!}{(6-1)!1!} (3c)^{6-1}.(d^2)^1+\frac{6!}{(6-2)!2!} (3c)^{6-2}.(d^2)^2+\frac{6!}{(6-3)!3!} (3c)^{6-3}.(d^2)^3+\frac{6!}{(6-4)!4!} (3c)^{6-4}.(d^2)^4+\frac{6!}{(6-5)!5!} (3c)^{6-5}.(d^2)^5+\frac{6!}{(6-6)!6!} (3c)^{6-6}.(d^2)^6$

⇒ $(3c+d^2)^6= \frac{6!}{(6-)!0!} (3c)^6.d^0+\frac{6!}{(5)!1!} (3c)^5.d^2+\frac{6!}{(4)!2!} (3c)^4.d^4+\frac{6!}{(6-3)!3!} (3c)^3.d^6+\frac{6!}{(2)!4!} (3c)^2.d^8+\frac{6!}{(1)!5!} (3c).d^{10}+\frac{6!}{(0)!6!} (3c)^0.d^{12}$

⇒ $(3c+d^2)^6=(3c)^6.d^0+\frac{720}{120} (3c)^5.d^2+\frac{720}{48} (3c)^4.d^4+\frac{720}{36} (3c)^3.d^6+\frac{720}{48} (3c)^2.d^8+\frac{720}{120} (3c).d^{10}+.d^{12}$

⇒ $(3c+d^2)^6=729c^6 + 1,458c^5d^2 + 1,215c^4d^4 + 540c^3d^6 + 135c^2d^8 + 18cd^{10} + d^{12}$

3 0

2 years ago

Read 2 more answers

it takes max 1.8 hours to walk home from work at a rate of 3.5km/h. how long would it take max to cover the same distance walkin

NikAS [45]

Time taken by Max to cover the same distance walking at 4.2 km/h is 1.5 hours

<h3><u>Solution:</u></h3>

Given it takes Max 1.8 hours to walk home from work at a rate of 3.5km/h

We have to find time taken by Max to cover the same distance walking at 4.2 km/h

<em><u>The relation between speed and time is given as:</u></em>

$speed = \frac{distance}{time}$

<em><u>CASE 1:</u></em>

It takes Max 1.8 hours to walk home from work at a rate of 3.5km/h

Let us first find the distance covered

Time taken = 1.8 hours and speed = 3.5 km/hr

$3.5 = \frac{distance}{1.8}\\\\distance = 3.5 \times 1.8 = 6.3$

Hence distance covered is 6.3 km

<em><u>Now we have to find the time taken to cover same 6.3 km walking at 4.2 km\hr</u></em>

$4.2 = \frac{6.3}{time taken}\\\\time taken = \frac{6.3}{4.2} = 1.5$

So time taken by Max to cover the same distance walking at 4.2 km/h is 1.5 hours

3 0

1 year ago

Angel owns 5/8 partnership in a bakery.<br> a. What percent of the bakery does Angel own?

OLEGan [10]

To start this, you would multiply 5/8 by 100 because you’re looking for a percentage.

5/8 x 100 = 62.5%

5 0

2 years ago

Emma needs to divide 7 by 1/2. Which strategy can Emma use to get the answer?

Juliette [100K]

Answer:

14

Step-by-step explanation:

Convert the fraction into a decimal

1/2 = 0.5

Divide

7/0.5 = 14

7 0

2 years ago

Use the data in the table to complete the sentence. x y –2 7 –1 6 0 5 1 4 The function has an average rate of change of ________

lora16 [44]

Answer: To find the average rate of change, evaluate the function at the given points.

Evaluate the difference of the function at the given points.

Divide the difference of the function at the given points with the difference of the given points.

Step-by-step explanation:

The Average of rate is -1.

Everytime it goes up by one the y goes down by 1 so it would be -1.

8 0

1 year ago