Answer:
Subtract 11 from both sides
Step-by-step explanation:
Answer:
Option 1:(x-4)^2+y^2=100
Step-by-step explanation:
Given center = (h,k) = (4,0)
The point (-2,8) lies on circle which means the distance between the point and center will be equal to the radius.
So,
The distance formula will be used:
Hence radius is 10.
The standard form of equation of circle is:
(x-h)^2+(y-k)^2 = r^2
Putting the values
(x-4)^2+(y-0)^2=10^2
(x-4)^2+y^2=100
Hence option 1 is correct ..
Answer:
a=-1
b=-9
c=9
d=3
e=3
f=2
g=1.5
Step-by-step explanation:
Well, he used one box to decorate his yard, that's for sure. Then he used 40 from the other box to decorate his porch and the rest inside his house. That rest might be anything between 1 and infinity. So there were at least 41 balloons in each box. I think the question is incomplete, please doublecheck it so I'll be able to give you more specific result.
Answer:
99.85%
Step-by-step explanation:
The lifespans of meerkats in a particular zoo are normally distributed. The average meerkat lives 10.4 years; the standard deviation is 1.9 years.
Use the empirical rule (68-95-99.7%) to estimate the probability of a meerkat living less than 16.1 years.
Solution:
The empirical rule states that for a normal distribution most of the data fall within three standard deviations (σ) of the mean (µ). That is 68% of the data falls within the first standard deviation (µ ± σ), 95% falls within the first two standard deviations (µ ± 2σ), and 99.7% falls within the first three standard deviations (µ ± 3σ).
Therefore:
68% falls within (10.4 ± 1.9). 68% falls within 8.5 years to 12.3 years
95% falls within (10.4 ± 2*1.9). 95% falls within 6.6 years to 14.2 years
99.7% falls within (10.4 ± 3*1.9). 68% falls within 4.7 years to 16.1 years
Probability of a meerkat living less than 16.1 years = 100% - (100% - 99.7%)/2 = 100% - 0.15% = 99.85%
