If s(x) = 2 – x2 and t(x) = 3x, which value is equivalent to (s circle t) (negative 7)?

Mathematics

2 answers:

Lisa [10]2 years ago

5 0

Answer:

-439

Step-by-step explanation:

(s circle t) (negative 7) is a notation for a compound function.

A compound function is a function that has as an argument another function.

Another notation for this compound function is s(t(-7)), that is, the result of the function t(-7) is the value that will be used in the function s(x).

So, first we calculate the value of t(-7):

t(x) = 3x

t(-7) = 3*(-7) = -21

Now, we apply this value for s(x):

s(x) = 2 - x2

s(t(-7)) = s(-21) = 2 - (-21)^2 = 2 - 441 = -439

Ymorist [56]2 years ago

4 0

Answer:

-439

Step-by-step explanation:

a on edge

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$\bf \qquad \textit{ inverse proportional variation}\\\\\\
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namely "w" varies inversely to </span> $\bf d^2$ or $\bf w=\cfrac{k}{d^2}$

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so $\bf w=\cfrac{k}{d^2}\qquad 
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\\\\\\
\textit{solve for "k", to find the}\\
\textit{"constant of variation"}\\
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