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dem82 [27]
2 years ago
8

If s(x) = 2 – x2 and t(x) = 3x, which value is equivalent to (s circle t) (negative 7)?

Mathematics
2 answers:
Lisa [10]2 years ago
5 0

Answer:

-439

Step-by-step explanation:

(s circle t) (negative 7) is a notation for a compound function.

A compound function is a function that has as an argument another function.

Another notation for this compound function is s(t(-7)), that is, the result of the function t(-7) is the value that will be used in the function s(x).

So, first we calculate the value of t(-7):

t(x) = 3x

t(-7) = 3*(-7) = -21

Now, we apply this value for s(x):

s(x) = 2 - x2

s(t(-7)) = s(-21) = 2 - (-21)^2 = 2 - 441 = -439

Ymorist [56]2 years ago
4 0

Answer:

-439

Step-by-step explanation:

a on edge

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2 Rita bought three and forty-eight hundredths pounds of bananas at the store. How is this number written in expanded notation?
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The cost of bananas = $ 3.48

This can be written as :                                                                                            

this number written in expanded notation as : (3 × 1) + (4 × 0.1) + (8 × 0.01)

3+0.4+0.08 = 3.48

Hence, 1st option is correct.                                                  

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Step-by-step explanation:

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Demand for Tablet Computers The quantity demanded per month, x, of a certain make of tablet computer is related to the average u
soldier1979 [14.2K]

x = f ( p ) = \frac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } } \\\\ \qquad { p ( t ) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \quad ( 0 \leq t \leq 60 ) }

Answer:

12.0 tablet computers/month

Step-by-step explanation:

The average price of the tablet 25 months from now will be:

p ( 25) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { 25 } } + 200 \\= \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \times 5 } + 200\\\\=\dfrac { 400 } { 1 + \dfrac { 5 } { 8 } } + 200\\p(25)=\dfrac { 5800 } {13}

Next, we determine the rate at which the quantity demanded changes with respect to time.

Using Chain Rule (and a calculator)

\dfrac{dx}{dt}= \dfrac{dx}{dp}\dfrac{dp}{dt}

\dfrac{dx}{dp}= \dfrac{d}{dp}\left[{ \dfrac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } }\right] =-\dfrac{100}{9}p(810,000-p^2)^{-1/2}

\dfrac{dp}{dt}=\dfrac{d}{dt}\left[\dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \right]=-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}

Therefore:

\dfrac{dx}{dt}= \left[-\dfrac{100}{9}p(810,000-p^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}\right]

Recall that at t=25, p(25)=\dfrac { 5800 } {13} \approx 446.15

Therefore:

\dfrac{dx}{dt}(25)= \left[-\dfrac{100}{9}\times 446.15(810,000-446.15^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt {25} \right]^{-2}25^{-1/2}\right]\\=12.009

The quantity demanded per month of the tablet computers will be changing at a rate of 12 tablet computers/month correct to 1 decimal place.

8 0
2 years ago
Twenty-five more than 3 times the quantity of a number decreased by 9 is 43 find the number
VashaNatasha [74]


9

equation- 25+ 3x - 9= 43


3 0
2 years ago
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