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Nata [24]
2 years ago
8

Figures R, S, and T are all scaled copies of one another. Figure S is a scaled copy of R using a scale factor of 3. Figure T is

a scaled copy of S using a scale factor of 2. Find the scale factors for each of the following:
1. From T to S

2. From S to R

3. From R to T

4. From T to R
Mathematics
1 answer:
MakcuM [25]2 years ago
4 0

<em><u>Answer:</u></em>

1/2

1/3

6

1/6

<em><u>Step-by-step explanation:</u></em>

When we are finding the opposite of a scale factor, the scale factor is always the reciprocal. E.g. From S to R, the scale factor is 3, so from R to S, the scale factor is 1/3 so:

1. From T to S, it's the reciprocal of the scale factor (2) so 1/2

2. From S to R, it's the reciprocal of the scale factor (3) so 1/3

3. From R to T, is the from a figure to a figure to a figure so we can multiply the two scale factors (2 and 3) to get 6

4. From T to R, that's the opposite of R to T, so it's the reciprocal of the scale factor from R to T (6) so 1/6

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lys-0071 [83]

Answer:

Pierre operates at a greater power level than Marie.

Marie and Pierre do  the same amount of work

Step-by-step explanation:

Mass of crate=60kg

Height of truck bed=1 m

Time=3s

Pierre's work done=60\times 1\times 9.8=588J

Using formula Work done=mgh

Where m=mass of object

g=Acceleration due to gravity=9.8m/s^2

Power=\frac{w}{t}

Using the formula

Pierre's power=\frac{588}{3}=196watt

Mass of box=2.5Kg

Total number of boxes=24

Total mass of boxes=2.5\times 24=60kg

Time=2 min=2\times 60=120s

1 min=60 s

Marie;s work done=60\times 1\times 9.8=588J

Marie's power=\frac{588}{120}=4.9watt

Pierre operates at a greater power level than Marie.

Marie and Pierre do  the same amount of work

7 0
2 years ago
Solve the system of equations below by graphing both equations with a pencil and paper. What is the solution?
Nataly [62]

Answer:

B    (2,1)

Step-by-step explanation:

7 0
2 years ago
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(-2x²y)³ / (xy²z)² * (-yz)² Hello guys, im having trouble with this babe...
Masja [62]
\frac{(-2x^2y)^3}{(xy^2z)^2(-yz)^2}

On top: (-2)³ = -2 × -2 × -2 = -8
(x²)³ = x^6 (the exponents multiply)
and of course, (y)³ = y³

On the bottom: (xy²z)² = x² y^4 z²
(-yz)² = y²z²
Multiplying these together, the exponents add and we get x² y^6 z^4.

\frac{-8x^6y^3}{x^2y^6z^4}

So, your reasoning is correct for what you have so far.

Your next step would be cancelling shared factors from the top and bottom.
Just like with regular fractions, if the numerator and denominator are divisible by the same number, you can divide them by it to simplify. (ex: 4/6 = 2/3)

Well, x^6 and x^2 are both divisible by x^2, right?
We can also cancel the y^3.

It might help to visualise the factors like this:

\frac{-8xxxxxxyyy}{xxyyyyyyzzzz}

Once you've cancelled out x² and y³ from each, you're left with

\boxed{\frac{-8x^4}{y^3z^4}}
7 0
2 years ago
Solve the inequality 6h−5(h−1)≤7h−11 and write the solution in interval notation. Use improper fractions if necessary.
Kobotan [32]

Answer:

h \geq 2\frac{2}[3}

Step-by-step explanation:

We solve the inequality similarly to how we would solve an equalitu.

6h - 5(h-1) \leq 7h - 11

6h - 5h + 5 \leq 7h - 11

h - 7h \leq -11 - 5/

-6h \leq -16

Multiplying everything by -1

6h \geq 16

Simplifying by 2

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h \geq \frac{8}{3}

8 divided by 3 is 2 with rest two. So as a improper fraction, the answer is:

h \geq 2\frac{2}[3}

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