Answer; I tink we can do it again
Explanation; wpfobidkdkbkgkeobhigifooefofof
Answer:
Step-by-step explanation:
The following is the logarithm quotient rule:

Plugging in the values we have above gives us the following:



Answer:
The correct answer is B The interquartile range for cars is about 7 mpg, and the interquartile range for minivans is about 3 mpg.
Step-by-step explanation: it makes sence and if youre using edge it is correct :)
Answer:
, it is the amount of money earned per number of hours of work, x
Step-by-step explanation:
Here we have two functions:

This function represents the amount of money (the earning) per unit x
Then we have the function

which represents the number of gallons of ice cream that Barrett makes per hour, where x is the number of hours he works.
Here we want to find the composite function
which means that we use the output of
as input for
. In this context, this means that the function
represents the amount of money earned per number of hours of work, x.
Substituting g(x) into the x of f(x), we find:

Answer:
The 95% confidence interval for the population variance is ![\left[0.219, \hspace{0.1cm} 0.807\right]\\\\](https://tex.z-dn.net/?f=%5Cleft%5B0.219%2C%20%5Chspace%7B0.1cm%7D%200.807%5Cright%5D%5C%5C%5C%5C)
The 95% confidence interval for the population mean is ![\left [15.112, \hspace{0.3cm}15.688\right]](https://tex.z-dn.net/?f=%5Cleft%20%5B15.112%2C%20%5Chspace%7B0.3cm%7D15.688%5Cright%5D)
Step-by-step explanation:
To solve this problem, a confidence interval of
for the population variance will be calculated.

Then, the
confidence interval for the population variance is given by:
Thus, the 95% confidence interval for the population variance is:![\\\\\left [\frac{(19-1)(0.6152)^2}{32.852}, \hspace{0.1cm}\frac{(19-1)(0.6152)^2}{8.907} \right ]=\left[0.219, \hspace{0.1cm} 0.807\right]\\\\](https://tex.z-dn.net/?f=%5C%5C%5C%5C%5Cleft%20%5B%5Cfrac%7B%2819-1%29%280.6152%29%5E2%7D%7B32.852%7D%2C%20%5Chspace%7B0.1cm%7D%5Cfrac%7B%2819-1%29%280.6152%29%5E2%7D%7B8.907%7D%20%5Cright%20%5D%3D%5Cleft%5B0.219%2C%20%5Chspace%7B0.1cm%7D%200.807%5Cright%5D%5C%5C%5C%5C)
On other hand,
A confidence interval of
for the population mean will be calculated

\
Thus, the 95\% confidence interval for the population mean is:![\\\\\left [15.40 - 2.093\sqrt{\frac{(0.6152)^2}{19}}, \hspace{0.3cm}15.40 + 2.093\sqrt{\frac{(0.6152)^2}{19}} \right ]=\left [15.112, \hspace{0.3cm}15.688\right] \\\\](https://tex.z-dn.net/?f=%5C%5C%5C%5C%5Cleft%20%5B15.40%20-%202.093%5Csqrt%7B%5Cfrac%7B%280.6152%29%5E2%7D%7B19%7D%7D%2C%20%5Chspace%7B0.3cm%7D15.40%20%2B%202.093%5Csqrt%7B%5Cfrac%7B%280.6152%29%5E2%7D%7B19%7D%7D%20%5Cright%20%5D%3D%5Cleft%20%5B15.112%2C%20%5Chspace%7B0.3cm%7D15.688%5Cright%5D%20%5C%5C%5C%5C)