Answer:
The absolute brightness of the Cepheid star after a period of 45 days is -5.95
Step-by-step explanation:
Since the absolute magnitude or brightness of a Cepheid star is related to its period or length of its pulse by
M = –2.78(log P) – 1.35 where M = absolute magnitude and P = period or length of pulse.
From our question, it is given that P = 45 days.
So, M = –2.78(log P) – 1.35
M = –2.78(log 45) – 1.35
M = –2.78(1.6532) – 1.35
M = -4.60 - 1.35
M = -5.95
So, the absolute magnitude or brightness M of a Cepheid star after a period P of 45 days is -5.95
Answer:
4589.75J
Step-by-step explanation:
Kinetic energy = 1/2 x M x v^2
Given
Mass M = 55.0kg
V = 12.92m/s
Kinetic energy
= 1/2 x 55.0 x (12.92)^2
= 1/2 x 55.0 x (12.92 x 12.92)
= 1/2 x 55.0 x 166.9
Multiply through
= 9179.5/2
= 4589.75J
10 x 62 is the equation for this problem because every row has 62 and there are 10 rows.
Converting feet to inches, 8*12=96 and 96*4=384. Next, 40*12=480. Since 384*x (if x represents the cost per inch of crown molding)=16*100=1600 cents due to that for every inch, we add x amount of money, we can find x to be 1600/384=800/192=400/96=200/48=100/24=50/12=25/6 by simply dividing both the numerator and denominator by 2 each time. Since we add x amount of money for every inch, and we have 480 inches, 480*x=480*25/6=2000 cents=2000/100=20 dollars is our answer
