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2 years ago

14

Seamus has a truck of chairs and tables for a party. There are 8 times as many chairs as tables, for a total of 56 chairs in the

truck. How many tables are in the truck?

1 answer:

DIA [1.3K]2 years ago

3 0

Answer:

7

Step-by-step explanation:

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If ce = 7x+4, find the value of x

Alex787 [66]

Hey there,

To find the value of x we can take the two, CD or DE and set them equal to CE.

First step is set the lines equal to each other:

x + 3 + 8x - 9 = 7x + 4

Now we combine like terms:

9x - 6 = 7x + 4

Then we subtract 7x from both sides:

2x - 6 = 4

Add 6 to both sides:

2x = 10

Lastly we divide both sides by 2:

x = 5

So the value of x would have to be 5.

Hope I helped,

Amna

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2 years ago

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Jeri finds a pile of money with at least $\$200$. If she puts $\$50$ of the pile in her left pocket, gives away $\frac23$ of the

Marizza181 [45]

Answer:

The possible values of the number of dollars in the original pile of money is ≥ $200 but < $350

Step-by-step explanation:

Here we have, pile of money ≥ $200

Amount in put the left pocket = $50

Fraction given away = 2/3 of rest of pile ≥ 2/3×150 ≥ $100

Amount put in right pocket = ≥ $150 - $100 ≥ $50

Total amount remaining with Jeri = $50 +≥ $50 ≥ $100

Also original pile - $200 < $100

Therefore where maximum amount given away to have more money = $200 we have

2/3× (original pile - 50) = $200

Maximum amount for original pile = $350

Therefore the possible values of the number of dollars in the original pile of money is ≥ $200 but < $350.

6 0

2 years ago

of the coins in Simone's collection 13/25 or quarters of these quarters 2/3 are state quarters what fraction of Simone's coins a

Rzqust [24]

I have no idea. I'm sorry I havne'nt work on this stuff since 6th grade..

3 0

2 years ago

The letters of the word mississippi are placed in a hat. what is the probability that the first two letters drawn are both i if

allochka39001 [22]

For the first letter drawn, there are no conditions/restrictions we need to consider. So, the number of ways to draw an i is:
$\text{Draw(i): } \frac{4}{11}$

For the second draw, the i is not replaced. That means, we've shrunk the sample space because we're dealing with less elements for the second draw. Firstly, one i disappears since we picked an "i" and there are 10 elements left, not 11.

Thus, to draw the second i, we have:
$\text{Draw(ii): } \frac{3}{10}$

$\text{P(drawing 2 i's): } \frac{4}{11} \cdot \frac{3}{10} = \frac{12}{110} = \frac{6}{55}$

3 0

2 years ago

Grace works as a salesperson at an electronics store and sells phones and phone accessories, and makes a fixed commission for ea

spayn [35]

Answer:

Commissions:

Accessoriy: $2

Phone: $9

Step-by-step explanation:

18p + 21a = 204

6p + 14a = 82

21a = 42

a = 2

p = [82 - 14(2)]/6 = 9

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2 years ago

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