Let the width of the yard be w.
Since the length is 18feet longer, l = w + 18
Perimeter for rectangle = 2(l + w)
2(l + w) = 72
2(w+18 + w) = 72 Divide 2 on both sides
(w + 18 + w) = 36
2w + 18 = 36
2w = 36 - 18
2w = 18 Divide 2 on both sides
w = 18/2
w = 9
Recall, length l = w + 18, l = 9 + 18 = 27
Hence width, w = 9, length,l = 27
Area of rectangle = l × w = 27 × 9 = 243
Area of rectangular yard = 243 square feet.
Answer:
The value of x for the given expression is 
Step-by-step explanation:
Given as :
The statement is , three fourths times x plus five fourths equals four times x
So, 
× x + 
= 4 × x
<u>Now, rearranging the equation</u>
i.e 4 x - × x =
Or, 4 x - 
=
Or, 
=
Or, 
=
Or, 13 x = × 4
Or, 13 x = 5
∴ x =
Hence, The value of x for the given expression is Answer
Quadratic equation: ax² + bx + c =0
x' = [-b+√(b²-4ac)]/2a and x" = [-b-√(b²-4ac)]/2a
6 = x² – 10x ; x² - 10x -6 =0
(a=1, b= - 10 and c = - 6
x' = [10+√(10²+4(1)(-6)]/2(1) and x" = [10-√(10²+4(1)(-6)]/2(1)
x' =5+√31 and x' = 5-√31
Answer:
The mean is the better method.
Step-by-step explanation:
The best way to meassure the average height is throught mean. The mean of a sample is the average of that sample's height, and it will be a good estimate for the population's average height.
The mode just finds the most frequent height. Even tough the most frequent height will influence the average height, knowing only what height is the most frequent one doesnt give you enough informtation about how the height is centrally distributed.
As for the median, it is fine to use the median of a sample to estimate the median of the population, but if you use the median to estimate the average height you may have a few issues. For example, if you include babies in your population, the babies will push the average height down a lot and they are far below te median height. This, as a result, will give you a median height of a sample way above the average height of the population, becuase median just weights every person's height the same, while average will weight extreme values more, in the sense that a small proportion of extreme values can push the average far from the median.
