The answer plz I need the answer

Two standard dice are rolled and their face values multiplied. What is the probability that the product is prime or ends in 0?

Trava [24]

The answer is 10/36 or 27.77%
here’s the working out

8 0

2 years ago

Please answer this as fast as you can In the graphic above, ΔABC ≅ ΔEDC by: HL. AAS. AAA. SSS.

Masja [62]

Answer:

Step-by-step explanation:

Triangles by definition have 3 sides. If the sides are corresponding then it is beneficial to us if they are the same length as well. If all 3 sides in one triangle are equal in length to the corresponding sides in another triangle, then the triangles are congruent by SSS (side-side-side). This is the case for us. Side EC is corresponding and congruent to side AC; side CD is corresponding and congruent to side CB; side ED is corresponding and congruent to side AB.

4 0

2 years ago

The U.S. Energy Information Administration (US EIA) reported that the average price for a gallon of regular gasoline is $2.94. T

Anit [1.1K]

Answer:

a) 25

b) 67

c) 97

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample. In this problem, $\sigma = 0.25$

(a) The desired margin of error is $0.10.

This is n when M = 0.1. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.1 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.1\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.1}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.1})^{2}$

$n = 24.01$

Rounding up to the nearest whole number, 25.

(b) The desired margin of error is $0.06.

This is n when M = 0.06. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.06 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.06\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.06}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.06})^{2}$

$n = 66.7$

Rounding up, 67

(c) The desired margin of error is $0.05.

This is n when M = 0.05. So

$M = z*\frac{\sigma}{\sqrt{n}}$

$0.05 = 1.96*\frac{0.25}{\sqrt{n}}$

$0.05\sqrt{n} = 1.96*0.25$

$\sqrt{n} = \frac{19.6*0.25}{0.05}$

$(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.05})^{2}$

$n = 96.04$

Rounding up, 97

8 0

1 year ago

Sociologists studying the behavior of high school freshmen in a certain state collected data from a random sample of freshmen in

timurjin [86]

Answer:

C

Step-by-step explanation:

Stay safe hope this helps

5 0

1 year ago

Read 2 more answers

Pablo generates the function f (x) = three-halves (five-halves) Superscript x minus 1 to determine the xth number in a sequence.

kondor19780726 [428]

Answer:

f(x + 1) = Five-halves f(x) (A)

Question:

The complete question as found in brainly( ID:13525864) is stated below.

Pablo generates the function f(x) = three-halves (five-halves) Superscript x minus 1 to determine the xth number in a sequence.

Which is an equivalent representation?

f(x + 1) = Five-halvesf(x)

f(x) = Five-halvesf(x + 1)

f(x + 1) = Three-halvesf(x)

f(x) = Three-halvesf(x + 1)

Step-by-step explanation:

f(x) = (3/2)(5/2)^(x-1)

Where 3/2 = three-halves and 5/2 = (five-halves)

To determine an equivalent representation, let's assign values to x to see the outcome and compare it with the options.

f(x) = (3/2)(5/2)^(x-1)

For x = 1

f(x) = (3/2)(5/2)^(1-1) = (3/2)(5/2)^(0)

f(x) =(3/2)(1) = 3/2

For x = 2

f(x) = (3/2)(5/2)^(2-1) = (3/2)(5/2)^(1)

f(x) =(3/2)(5/2)

So from the above assigned values

f(x=1) = 3/2

f(x=2) = f(x + 1) = f(1 + 1)

f(x + 1) = (3/2)(5/2)

Since f(x) = 3/2

f(x+1) = (3/2)(5/2) = f(x) × 5/2 = 5/2f(x)

From the options, an equivalent representation: f(x + 1) = Five-halves f(x)

(A)

5 0

1 year ago