Answer:
The sides of ∆ABC are 30 units, 40 units, and 60 units long.
The perimeter will be = 
units
Given is that ∆ABC and ∆XYZ are similar and the corresponding sides of ∆XYZ are 'r' times as long as the sides of ∆ABC.
So, perimeter of ∆XYZ will be : 
units.
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The area of ∆ABC is n square units, so area of ∆XYZ will be :
= 
= 
square units.
Answer:
H0 ; μ ≤ 4 pCi/L
Ha ; μ > 4 pCi/L
The null hypothesis is that the concentration of dangerous, cancer-causing radon gas in her classroom is less than or equal to the safe level of 4pCi/L
H0 ; μ ≤ 4 pCi/L
The alternative hypothesis is that the concentration of dangerous, cancer-causing radon gas in her classroom is greater than the safe level of 4pCi/L.
Ha ; μ > 4 pCi/L
Step-by-step explanation:
The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.
The null hypothesis is that the concentration of dangerous, cancer-causing radon gas in her classroom is less than or equal to the safe level of 4pCi/L
H0 ; μ ≤ 4 pCi/L
The alternative hypothesis is that the concentration of dangerous, cancer-causing radon gas in her classroom is greater than the safe level of 4pCi/L.
Ha ; μ > 4 pCi/L
Answer:
Lewie Survey produces less valid result.
Step-by-step explanation:
Given:
1. Kelvin surveys every other person leaving the food area.
2. Lewie surveys every fifth person leaving the mall's main entrance.
Therefore,
Kelvin will able to produce valid result as he is surveying every person who is leaving food court.
Means,
There are high chances that would have bought food from the court.
Whereas,
Lewie is surveying every fifth person leaving the the mall's entrance.
Therefore,
Here probability to produce valid result is less as they may have not buy food or they may visited other shops.
So, Lewie survey will produce less valid result.
Answer: 
and 
will be correct.
Explanation:
Given: two quadrilaterals having verticals P, N, O,M and S,T,V,U are congruent, where, OM is congruent or equal to TS and 
.
in quadrilaterals NPOM and VUTS-
since, the condition 
and, side UV=side OM follow for the above quadrilateral. (According to the figure)
then we can say according to the property of quadrilateral, their corresponding sides must be congruent. so they are congruent.
similarly, these two conditions also follow in the case of
we can understand it by making the figures.
