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katovenus [111]

1 year ago

9

An element with a mass of 100 grams decays by 20.5% per minute. To the nearest minute, how long will it be until there are 10 gr

ams of the element remaining?

2 answers:

vekshin11 year ago

7 0

Every minute, the mass is reduced by 20.5%, making it 79.5% of the new mass. We can use this to set up an equation where x = minutes.

100 * (0.795)^x = 10

Solve for x.

Divide by 100 on both sides

0.795^x = 1/10

log (0.795^x) = log (1/10)

x * log (0.795) = log (1/10)

x = log (1/10) / log (0.795)

x ≈ 10

10 minutes

ioda1 year ago

3 0

Answer:

About 10 minutes.

Step-by-step explanation:

Let's make an equation to model this situation. This is called exponential decay, so we'll need to use an exponent soon. We're starting with 100 grams:

100

It decays (this means subtraction) by 20.5% per minute. With m = minute:

100(1 - .205)^m

And we want to end up with 10 grams remaining:

100(1 - .205)^m = 10

Let's solve for m now!

100(1 - .205)^m = 10

(1 - .205)^m = 10/100

.795^m = .1

log.795(.1) = m

m = 10.037 = <u>about 10 minutes</u>

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2 years ago

A piece of paper is to display ~128~ 128 space, 128, space square inches of text. If there are to be one-inch margins on both si

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The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches

Step-by-step explanation:

We have that:

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Divide through by 2

$256=y^2$

Take square roots of both sides

$\sqrt{256=y^2$

$16=y$

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To double-check;

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Step-by-step explanation:

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2 years ago