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2 years ago

the mean of 11 numbers is 7. one of the numbers, 13, is deleted. what is the mean of the remaining 10 numbers?

1 answer:

7 0

The mean is the average of the numbers, so if x = all 11 numbers added together, then you have the equation:

x / 11 = 7, so x = 77 (this is all of the numbers added together)

if the number 13 is removed, the equation becomes:

(77 - 13) / 10 = M (M is the new mean)

so the new mean is 6.4

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Answer:

Probability that 32 or more from this sample used Internet Explorer as their browser is 0.9015.

Step-by-step explanation:

We are given that according to Net Market Share, Microsoft's Internet Explorer browser has 53.4% of the global market.

A random sample of 70 users was selected.

Let $\hat p$ = sample proportion of users who used Internet Explorer as their browser.

The z score probability distribution for sample proportion is given by;

Z = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, p = population proportion of users who use internet explorer = 53.4%

$\hat p$ = sample proportion = $\frac{32}{70}$ = 0.457

n = sample of users = 70

Now, probability that 32 or more from this sample used Internet Explorer as their browser is given by = P( $\hat p$ $\geq$ 0.457)

P( $\hat p$ $\geq$ 0.457) = P( $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ $\geq$ $\frac{0.457-0.534}{\sqrt{\frac{0.457(1-0.457)}{70} } }$ ) = P(Z $\geq$ -1.29)

= P(Z $\leq$ 1.29) = 0.9015

The above probability is calculated by looking at the value of x = 1.29 in the z table which has an area of 0.9015.

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2 years ago

Joaquin and Trisha are playing a game in which the lower median wins the game. Their scores are shown below.

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Median is defined as the middle term when the scores are arranged in increasing/decreasing order.

Joaquin's scores: 58, 62, 72, 75, 85, 91 Median: 73.5
Trisha's scores: 55, 74, 76, 90, 91, 92 Median: 83

The answer is letter A.

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1 year ago

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Denise is constructing A square.

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