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maw [93]
2 years ago
5

In how many ways can you receive four cards of the same face value and one card from the other 48 available cards?

Mathematics
1 answer:
frozen [14]2 years ago
5 0
There are 13 sets of 4 cards in a deck of card. So, there are 13 ways to get four cards of the same face value. The next card you pick will always be a different face value. So, essentially, you have 13 x 48 combinations of 5 cards that you can pick from the deck where you have 4 cards of the same face value and 1 card of a different face value.

13 x 48 = 624.


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Answer:

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Step-by-step explanation:

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Answer: We are given:

\mu=247,\sigma=60

We need to find the z scores for the following vacation expense amounts:

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We know that z score formula is:

z=\frac{x-\mu}{\sigma}

When x = 197, the z score is:

z=\frac{197-247}{60}

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When x = 310, the z score is:

z=\frac{310-247}{60}

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Therefore, the z scores for the vacation expense amounts $197 per day, $277 per day, and $310 per day are -0.83, 0.5 and 1.05 respectively


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Answer:

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Step-by-step explanation:

Let's translate what you've written in words to an expression with mathematical symbols.

\frac{\sqrt6 +\sqrt{11}}{\sqrt{5} + \sqrt{3}}

To solve this, you need to multiply both the numerator and denominator with the conjugate of the denominator.

\frac{\sqrt6 +\sqrt{11}}{\sqrt{5} + \sqrt{3}} \times \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} - \sqrt{3}} = \frac{\sqrt{30} - \sqrt{18} + \sqrt{55} - \sqrt{33}}{2}

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