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Paraphin [41]
2 years ago
7

What is the following quotient? sqrt 6 + sqrt 11 / sqrt 5 +sqrt 3

Mathematics
2 answers:
Nadya [2.5K]2 years ago
6 0

The answer is B) Link below

just olya [345]2 years ago
5 0

Answer:

\frac{\sqrt6 +\sqrt{11}}{\sqrt{5} + \sqrt{3}} \times \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} - \sqrt{3}} = \frac{\sqrt{30} - \sqrt{18} + \sqrt{55} - \sqrt{33}}{2}

Step-by-step explanation:

Let's translate what you've written in words to an expression with mathematical symbols.

\frac{\sqrt6 +\sqrt{11}}{\sqrt{5} + \sqrt{3}}

To solve this, you need to multiply both the numerator and denominator with the conjugate of the denominator.

\frac{\sqrt6 +\sqrt{11}}{\sqrt{5} + \sqrt{3}} \times \frac{\sqrt{5} - \sqrt{3}}{\sqrt{5} - \sqrt{3}} = \frac{\sqrt{30} - \sqrt{18} + \sqrt{55} - \sqrt{33}}{2}

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Answer:

The absolute brightness of the Cepheid star after a period of 45 days is -5.95

Step-by-step explanation:

Since the absolute magnitude or brightness of a Cepheid star is related to its period or length of its pulse by

M = –2.78(log P) – 1.35 where M = absolute magnitude and P = period or length of pulse.

From our question, it is given that P = 45 days.

So, M = –2.78(log P) – 1.35

M = –2.78(log 45) – 1.35

M = –2.78(1.6532) – 1.35

M = -4.60 - 1.35

M = -5.95

So, the absolute magnitude or brightness M of a Cepheid star after a period P of 45 days is -5.95

8 0
2 years ago
Read 2 more answers
Use the figure below to estimate the indicated derivatives, or state that they do not exist. If a derivative does not exist, ent
tatiyna
F(x)=3x/2 for 0≤x≤2 
<span>.....=6 - 3x/2 for 2<x≤4 </span>
<span>g(x) = -x/4 + 1 for 0≤x≤4 and g'(x)=-1/4 </span>
<span>so h(x)= f(g(x)) = (3/2)(-¼x+1)=-3x/8 + 3/2 for 0≤x≤2 </span>
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<span>When x=2, g(2)=1/2 so h'(2)=g'(2)f '(1/2)= -(1/4)(3/2)=-3/8 </span>

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2 years ago
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RUDIKE [14]

Answer:

x=1\,,\,y=t\,,\,z=t

Step-by-step explanation:

A line is a one-dimensional figure that has no thickness and extends infinitely in both directions.

A line segment is a line that has two end-points and a ray is a line that has one end-point.

Given equation is x^2+y^2-z^2=1

To find : a line that lies entirely in the set defined by the given equation.

Solution:

Take x=1\,,\,y=t\,,\,z=t

Check:

L.H.S=1^2+t^2-t^2=1+0=1=R.H.S

Therefore, x=1\,,\,y=t\,,\,z=t satisfy the given equation.

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Function f is a cosine function with period 8π, amplitude 3, and a local maximum at f(0) = –3. What is the equation of the midli
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Answer:

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Since there is no indication of a shift in the graph of f(x) = 3cos(-0.25x), then the midline must be the normal midline for a cosine or sine function which is: y = 0.

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7. A hotelier conducted a survey of guests staying at her hotel. The table shows some
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Answer:

here's the solution :-

Step-by-step explanation:

i hope it helped...

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